HTML: Determine the Precise Location of a Div Element That is Centered

Question

Imagine I have this image:

Is there a way for me to determine the x/y or left/top properties of my canvas if it is centered using the following CSS:

#canvas-container {
        width: 100px;
        height:100px;
        margin: 0px auto;
    }

Note:

$('#myCanvas')[0].style.top returns ""

Answer 1

Answer №1

For obtaining the position of an element with respect to the document, you can utilize the offset() method:

var elementTop = $('#myCanvas').offset().top,
    elementLeft = $('#myCanvas').offset().left;

Answer 2

For obtaining the position of an element with respect to the document, you can utilize the offset() method:

var elementTop = $('#myCanvas').offset().top,
    elementLeft = $('#myCanvas').offset().left;

Answer 3

To get the correct positioning values, you can use either .offset() or .position():

If you require absolute left/top values:

var offLeft = $('#mainFrame').offset().left;
var offTop = $('#mainFrame').offset().top;

If you need relative positioning for the element's left/top values:

var posLeft = $('#mainFrame').position().left;
var posTop = $('#mainFrame').position().top;

Answer 4

To get the correct positioning values, you can use either .offset() or .position():

If you require absolute left/top values:

var offLeft = $('#mainFrame').offset().left;
var offTop = $('#mainFrame').offset().top;

If you need relative positioning for the element's left/top values:

var posLeft = $('#mainFrame').position().left;
var posTop = $('#mainFrame').position().top;

Answer 5

Implementing JQuery Library

$('#myCanvas').first().offset();

// alternatively

$('#myCanvas:first-of-type').offset();

Answer 6

Implementing JQuery Library

$('#myCanvas').first().offset();

// alternatively

$('#myCanvas:first-of-type').offset();