Is there a way to style items 1 through 10 in CSS without using nth-child selectors individually?
Instead of doing:
&.nth-child(1) { //style }
&.nth-child(2) { //style }
&.nth-child(3) { //style }
I'm looking for a range selector in CSS that can help achieve this.
Utilize the :nth-child selector with an equation in the format an+b, where you replace a and b with integers, and n is 0, 1, 2,.....
li:nth-child(-n+10) {
color: red
}<ol>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
</ol>UPDATE : To target elements within a range, use multiple :nth-child selectors.
li:nth-child(n+5):nth-child(-n+10) {
color: red
}<ol>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
<li>a</li>
</ol>The following code snippet is designed to apply CSS styles to elements within the range of 2 to 3. Feel free to customize it as needed.
Explanation:
nth-child(n+2) selects elements starting from the 2nd position and beyond.
nth-child(-n+3) selects elements starting from the 3rd position backwards.
By combining these two, we create a specific range.
li:nth-child(n+2):nth-child(-n+3){
background: #000;
color: #fff
}<li>1</li>
<li>1</li>
<li>1</li>
<li>1</li>
<li>1</li>
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