How do I get the JavaScript If Style Color to function correctly?

Having some trouble with a basic if condition that checks the color of an element...

function adjustColorScheme(element) {
          if (element.target.style.color == "#1abc9c"){
            // Leave as is
          } 
          else { // Do something }

However, it doesn't seem to be functioning properly. When I use generic names like "Yellow, green, etc" it works fine. Any suggestions or advice?

Answer №1

The style.color attribute provides either a direct color name or RGB value, rather than a hex code. To work with your specific situation, you'll need to convert your hex code to RGB first and then compare it with style.color. One approach is to create a utility function

function getRgbFromHex(hexColorCode){
  const hexCode =  hexColorCode.startsWith('#') ? hexColorCode.substr(1) : hexColorCode;
  const hexR = hexCode.substring(0,2);
  const hexG = hexCode.substring(2,4);
  const hexB = hexCode.substring(4,6);
  
  return `rgb(${parseInt(hexR, 16)},${parseInt(hexG, 16)},${parseInt(hexB, 16)})`
  }

Afterwards, you can adjust your if condition as follows UPDATE Removing spaces from style.color

if (element.target.style.color.replace(/\s/g,'') == getRgbFromHex("#1abc9c"))

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