How can you ensure that an image reaches its full width and height without sacrificing its aspect ratio?

Is there a way to resize an image within its container without sacrificing its aspect ratio? It needs to work in IE9 and I can't use background images or JavaScript.

In my example, both images are smaller than the container but some may be larger and need to be scaled down.

To scale down images larger than their container, you can use the following CSS:

img {
 height: auto;
 width: auto;
 max-height: 100%;
 max-width: 100%;
}

But how can we trick the browser into thinking the image is larger than it actually is, similar to using the sizes attribute with the picture element?

https://i.sstatic.net/KCaZa.jpg

http://codepen.io/anon/pen/KdaboK

<div class="one">
<img src="http://www.nwhgeopark.com/wp-content/uploads/landscape.jpg" />
</div>
<div class="one">
<img src="http://ecx.images-amazon.com/images/I/519fW0fHKbL._SY300_.jpg" />
</div>

.one {
  border: 1px solid red;
  float: left;
  margin: 20px;
  height: 500px;
  width: 500px;

}

img {

}

Answer №1

If you want to apply different styles to images based on their orientation, you can utilize this jQuery script:

$(document).ready(function() {
  var imgs = $('img');
  imgs.each(function(){
    var img = $(this);
    var width = img.width(); 
    var height = img.height();
    if(width < height){
       img.addClass('portrait');
    }else{
       img.addClass('landscape');
    }
  })
});

Then, add the following CSS to style the images accordingly:

.landscape {
    width:100%;
    height:auto;  
}

.portrait {
    height:100%;
    width:auto;
}

This setup will give you the desired behavior for your images. Check it out in action on JSFIDDLE.

Answer №2

To dynamically fetch the dimensions of an image using jQuery, calculate the multiplication factor based on the container's width and then adjust the image size accordingly...

<script>
getImageDimensions($('#image'), function(width, height) {
$('#details').text(width + ',' + height);
var scaleFactor = ContainerWidth / width;
$(img).css({'width': width * scaleFactor +'px', 
'height': height * scaleFactor + 'px'});
});

function getImageDimensions(img, callback) {
var $img = $(img);

var timer = setInterval(function() {
    var w = $img[0].naturalWidth,
        h = $img[0].naturalHeight;
    if (w && h) {
        clearInterval(timer);
        callback.apply(this, [w, h]);
    }
}, 30);
}
</script>

Answer №3

In my opinion, a straightforward approach would be to categorize images based on their orientation - portrait or landscape, and then implement a responsive design rule. Give this code snippet a try, it should do the trick

<div class="one">
<img class="landscape" src="http://www.example.com/landscape.jpg" />
</div>
<div class="one">
<img class="portrait" src="http://www.example.com/portrait.jpg" />
</div>

.one {
  border: 2px solid blue;
  float: right;
  margin: 30px;
  height: 600px;
  width: 600px;

}

img.landscape {
  width: 90% !important;
  height: auto !important;
}

img.portrait {
  height: 90% !important;
  width: auto !important;
}

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