Here is the code snippet that I am using:
$(document).ready(function() {
$.fn.addRemoveButton = function() {
alert(1);
};
$.addRemoveButton();
});
When I run this code, I encounter the following error in Firebug:
TypeError: $.addRemoveButton is not a function $.addRemoveButton();
I am curious to understand why this error is happening and how can I resolve it. Any insights or suggestions would be greatly appreciated.
To make it work, you must create a selector. Here is how you can do it:
$(document).ready(function() {
$.fn.addButtonRemover = function() {
alert(1);
};
$(document).addButtonRemover();
});
It is important to implement this in every DOM element.
Illustration
Sample jQuery Script
$(function()
{
$.fn.customFunction = function() {
alert(1);
};
$('#customDiv').customFunction();
});
HTML Markup
<div id="customDiv"></div>
Instead of defining it as a jQuery plugin, consider creating it as a global function:
$(document).ready(function() {
$.addRemoveButton = function() { // removed the .fn
alert(1);
};
$.addRemoveButton();
});
By binding the function to the jQuery object in this way, you can easily use it just like in the original example provided.
To learn more about the distinction between jQuery.fn.method and jQuery.method, check out this post
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