Designing a drop-down menu that appears visually above its parent

As I design a menu positioned at the bottom using position:absolute; bottom:0, I want the submenu items to align perfectly above their parent. Each li should appear above the ul itself.

The trick to achieving this is by applying a negative margin. However, the challenge lies in defining the pixel amount based on the uppermost pixel of the box rather than the bottommost li item.

With a dynamic submenu and a fixed negative margin, the submenu above the main menu may end up not displaying correctly. It could appear far above or below the menu itself.

I am seeking a solution to this dilemma. I have considered three possible options, but I'm unsure how to implement any of them:
A. Calculate the negative margin value to be based on the bottom pixel of the box (similar to how distances are calculated in Photoshop with a focal point).
B. Use a dynamic option like

li:calc(<amount of list items * -23px + 20px)
, possibly with jQuery.
C. Come up with a better solution that you may have in mind. :)

Thank you!

P.S. The JSfiddle link showcasing my current setup can be found here, but please note that it is not functioning optimally: Here

Answer №1

Check out this demonstration:

http://jsfiddle.net/LuuAb/2/

var position = $('#filters').scrollTop()+$('#filters').height();
$(".option-set").css({bottom:''+position+'px'});

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