Creating a right triangle with a background filled with linear gradients: tips and tricks

Looking to create a right triangle with a linear-gradient background color in CSS? Wondering if it's possible?

Check out the code I currently have for a right triangle with a single background color. You can also find the same code here.

<style>
body {
  position: relative;
  height: 100vh;
  width: 100vw;
  background: lightgrey;
}

.wrapper {
  width: 760px;
  height: 35px;
  position: absolute;
  top: 50%;
  left: 50%;
  transform: translate(-50%, -50%);
}

.triangle {
  border-right-width: 760px;
  border-bottom-width: 35px;
  position: absolute;
  bottom: 0;
  left: 0;
  width: 0;
  height: 0;
  border-bottom-style: solid;
  border-right-style: solid;
  border-bottom-color: red;
  border-right-color: transparent;
}
</style>    

<body>
<div class="wrapper">
   <div class="triangle"><!-- ### --></div>
</div>
</body>

Wanting to achieve a right triangle with a linear-gradient background that transitions from orange to red from left to right. The area surrounding the triangle must remain transparent.

Answer №1

To optimize your code, consider utilizing the clip-path property instead. This will streamline your markup and allow for easy integration of a linear-gradient background.

Check out this Codepen demo


.triangle {
  display: block;
  max-width: 760px;
  height: 35px;
  background: linear-gradient(to right, orange, red);
  clip-path: polygon(0 0, 100% 100%, 0 100%)
}
<span class="triangle"></span>

Additionally, I opted for max-width over width to demonstrate responsive design possibilities.

Answer №2

It appears that you are in search of the border-image property:

border-image: linear-gradient(to top right, orange, red 50%, transparent 51%, transparent);
is likely what you need

Here is a demonstration of the solution:

.triangle {
    border-right-width: 760px;
    border-bottom-width: 35px;
    position: absolute;
    bottom: 0;
    left: 0;
    width: 0;
    height: 0;
    border-bottom-style: solid;
    border-right-style: solid;
    border-bottom-color: red;
    border-right-color: transparent;
    border-image: linear-gradient(to right top, orange, red 50%, transparent 51%, transparent);
}
<div class="wrapper">
  <div class="triangle"><!-- ### --></div>
</div>

Answer №3

If you want to achieve a triangle effect without transparency, you can try using multiple background layers. One approach is to overlay a triangle on top of a gradient with the same color as the main background:

.triangle { 
  max-width: 300px;
  height: 50px;
  background: 
    linear-gradient(to top right,transparent 49%,#fff 50%),
    linear-gradient(to right, blue, red);
}
<div class="triangle"></div>

Alternatively, you can use skew transformation and overflow properties to create a triangle with transparency:

.triangle { 
  max-width: 300px;
  height: 50px;
  overflow:hidden;
}
.triangle:before {
  content:"";
  display:block;
  height:100%;
  width:100%;
  background: linear-gradient(to right, blue, red);
  transform-origin:left;
  transform:skewY(10deg);
}
<div class="triangle"></div>

Another method is to use SVG for creating a triangle:

svg {
  width:300px;
}
<svg viewBox="0 0 300 100">
  <defs>
    <linearGradient id="grad" x1="0%" y1="0%" x2="100%" y2="0%">
      <stop offset="0%" stop-color="blue" />
      <stop offset="100%" stop-color="red" />
    </linearGradient>
  </defs>
  <polygon points='0,0 300,100 0,100' fill="url(#grad)" />
</svg>

Answer №4

Link to the code snippet

I've designed a gradient background with a right triangle shape.

Feel free to examine the code below:

<div class="gradient-block"></div>

.gradient-block{
    width:200px;
    height:180px;
    -webkit-clip-path: polygon(0 0, 0% 100%, 100% 59%);
    clip-path: polygon(0 0, 0% 100%, 100% 59%);
    display:inline-block;
    background: #8c3310; /* Old browsers */
    background: -moz-linear-gradient(top, #8c3310 0%, #bf6e4e 100%); 
    background: -webkit-linear-gradient(top, #8c3310 0%,#bf6e4e 100%);
    background: linear-gradient(to bottom, #8c3310 0%,#bf6e4e 100%); 
    filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#8c3310', endColorstr='#bf6e4e',GradientType=0 ); 
}

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