I'm facing an issue with a table row that contains 3 cells with values A, B, and C. The table is currently taking up the full width of the screen, but I want the second and third cells to be displayed in their correct size while allowing the first cell to take up the remaining space. Since the cells are dynamically sized, I can't simply set their widths manually. Does anyone know how I can achieve this layout?
To ensure that the table is fully responsive, you can set the width of the table to 100%, A to 100%, and B and C to auto. This method has been tested and proven to work effectively.
<table border="1px" width="100%">
<tr>
<td width="100%">A</td>
<td width="auto">BB</td>
<td width="auto">CCC</td>
</tr>
</table>
Enter X and Z in inches while setting Y to occupy the entire screen width.
After reading Rune's answer and Pistos' comment, I was able to get closer to my desired result. The final step involved adding style="white-space:nowrap" to the non-greedy columns. Here is the updated code:
<table border="1px" width="100%">
<tr>
<td width="100%">A wide column</td>
<td style="white-space:nowrap">Compact column 1</td>
<td style="white-space:nowrap">Another compact column</td>
</tr>
</table>
This solution worked effectively for me in Firefox 25.
After experimenting with Diodeus and Rune's strategies, unfortunately they did not solve my particular issue. In the end, I resorted to merging cells B and C since no other solution seemed applicable. Appreciate your assistance.
Give it a shot,
<table border="1px" width="100%">
<tr>
<td width="100%" height="100" style="background:#ff0000; display:block">X</td>
<td width="100%" height="100" style="background:#00ff00; display:block">YY</td>
<td width="100%" height="100" style="background:#ff00ff; display:block">ZZZ</td>
</tr>
</table>
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