Checking if an Element is Visible in Selenium

Question

Checking if an Element is Visible in Selenium

Is there a way to determine if an element is within the visible viewport of a browser using Selenium?

I attempted to do this by comparing the dimensions and locations of the element and the browser window. However, I encountered an issue where the Y value returned a large number due to page scrolling.

Dimension weD = element.getSize(); // getting element dimensions
Point weP = element.getLocation(); // getting element location

Dimension d = driver.manage().window().getSize(); // getting browser dimensions
int x = d.getWidth(); //browser width
int y = d.getHeight(); //browser height
int x2 = weD.getWidth() + ewp.getX();
int y2 = weD.getHeight() + ewp.getY();
return x2 <= x && y2 <= y;

If you have experience with this issue, could you please provide any solutions or insights?

java css selenium viewport

Answer 1

Answer №1

To detect if an element is visible in the viewport using the API directly may not be possible, so you might need to resort to a script injection method.

One effective way to check if an element is within the viewport is by retrieving the element at the specified location using document.elementFromPoint. If the element is not within the viewport, it will return null; otherwise, it will return your desired element or one of its descendants.

public static Boolean isVisibleInViewport(WebElement element) {
  WebDriver driver = ((RemoteWebElement)element).getWrappedDriver();

  return (Boolean)((JavascriptExecutor)driver).executeScript(
      "var elem = arguments[0],                 " +
      "  box = elem.getBoundingClientRect(),    " +
      "  cx = box.left + box.width / 2,         " +
      "  cy = box.top + box.height / 2,         " +
      "  e = document.elementFromPoint(cx, cy); " +
      "for (; e; e = e.parentElement) {         " +
      "  if (e === elem)                        " +
      "    return true;                         " +
      "}                                        " +
      "return false;                            "
      , element);
}

Answer 2

To detect if an element is visible in the viewport using the API directly may not be possible, so you might need to resort to a script injection method.

One effective way to check if an element is within the viewport is by retrieving the element at the specified location using document.elementFromPoint. If the element is not within the viewport, it will return null; otherwise, it will return your desired element or one of its descendants.

public static Boolean isVisibleInViewport(WebElement element) {
  WebDriver driver = ((RemoteWebElement)element).getWrappedDriver();

  return (Boolean)((JavascriptExecutor)driver).executeScript(
      "var elem = arguments[0],                 " +
      "  box = elem.getBoundingClientRect(),    " +
      "  cx = box.left + box.width / 2,         " +
      "  cy = box.top + box.height / 2,         " +
      "  e = document.elementFromPoint(cx, cy); " +
      "for (; e; e = e.parentElement) {         " +
      "  if (e === elem)                        " +
      "    return true;                         " +
      "}                                        " +
      "return false;                            "
      , element);
}

Answer 3

Answer №2

Special shoutout to Florent B. Here's the Python conversion:

def check_element_visibility(driver, element) -> bool:
    return driver.execute_script("var elem = arguments[0],                 " 
                                 "  box = elem.getBoundingClientRect(),    " 
                                 "  cx = box.left + box.width / 2,         " 
                                 "  cy = box.top + box.height / 2,         " 
                                 "  e = document.elementFromPoint(cx, cy); " 
                                 "for (; e; e = e.parentElement) {         " 
                                 "  if (e === elem)                        " 
                                 "    return true;                         " 
                                 "}                                        " 
                                 "return false;                            "
                                 , element)

Answer 4

Special shoutout to Florent B. Here's the Python conversion:

def check_element_visibility(driver, element) -> bool:
    return driver.execute_script("var elem = arguments[0],                 " 
                                 "  box = elem.getBoundingClientRect(),    " 
                                 "  cx = box.left + box.width / 2,         " 
                                 "  cy = box.top + box.height / 2,         " 
                                 "  e = document.elementFromPoint(cx, cy); " 
                                 "for (; e; e = e.parentElement) {         " 
                                 "  if (e === elem)                        " 
                                 "    return true;                         " 
                                 "}                                        " 
                                 "return false;                            "
                                 , element)

Answer 5

Answer №3

Big thanks to Florent B. and Ben Moskovitch for their contribution! Translated into C# 😉:

private bool CheckIfElementIsVisibleInViewport(IWebElement element) => (bool)((IJavaScriptExecutor)_webDriver).ExecuteScript("var elem = arguments[0], box = elem.getBoundingClientRect(), cx = box.left + box.width / 2,  cy = box.top + box.height / 2,  e = document.elementFromPoint(cx, cy); for (; e; e = e.parentElement) { if (e === elem) return true;} return false;", element);

Remember to have _webDriver as your WebDriver instance in the same class where this method is located.

Answer 6

Big thanks to Florent B. and Ben Moskovitch for their contribution! Translated into C# 😉:

private bool CheckIfElementIsVisibleInViewport(IWebElement element) => (bool)((IJavaScriptExecutor)_webDriver).ExecuteScript("var elem = arguments[0], box = elem.getBoundingClientRect(), cx = box.left + box.width / 2,  cy = box.top + box.height / 2,  e = document.elementFromPoint(cx, cy); for (; e; e = e.parentElement) { if (e === elem) return true;} return false;", element);

Remember to have _webDriver as your WebDriver instance in the same class where this method is located.

Answer 7

Answer №4

To determine the position of an element, you can use the yth attribute

yth = int(driver.execute_script("return document.querySelector('{el_selector}').getBoundingClientRect()".format(el_selector=el_selector)))

Answer 8

To determine the position of an element, you can use the yth attribute

yth = int(driver.execute_script("return document.querySelector('{el_selector}').getBoundingClientRect()".format(el_selector=el_selector)))

Checking if an Element is Visible in Selenium

Answer №1

Answer №2

Answer №3

Answer №4

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