Checking and locating elements using Jquery's distinctive style

Within my code, I am searching for the DIV element that has the class .se and also has the attribute display: block. Once found, I need to retrieve the ID of this particular DIV.

Unfortunately, it seems like my current approach is not correct.

var usedse = $(".se").filter(function() {
    return $(this).css('display') === 'block';
}).attr("id");

Would you be able to assist me in resolving this issue? Thank you!

Answer №1

Here is my suggestion:

let visibleElementId = $('.se:visible').attr('id');
if(visibleElementId) {
    alert(visibleElementId);
}

Answer №2

When working with .filter(), you have the ability to create custom logic... By targeting all elements with the class <div class='se'> and verifying that their CSS property display is set to block, you can retrieve the id of the first matching element.

var selectedSE = $("div.se").filter(function() { 
   return $(this).css('display') == 'block';
}).attr("id");

Answer №3

The method you have chosen to implement is inaccurate, consider the following alternative approach:

if ($("section.show").css('visibility') == 'visible') {
   var sectionId = $("section.show").attr('id');
   console.log(sectionId);
}

Answer №4

There are a couple of approaches you could take.

One option is to utilize the attribute selector, which will select all elements with the classes se and have the CSS property display set:

$(".se [style*='display']").attr('id');

Alternatively, you could use the .css() method to check the actual value of a specific CSS property:

var $possibles = $(".se"), id;
for ($el in $possibles)
    if ($el.css('display') === 'block') id = $el.attr('id');

However, I'm curious about the reason behind this task. It feels like there might be a more optimal solution to the problem at hand... perhaps assigning a class to the element could simplify things (although this may not always be feasible depending on the situation)?

Answer №5

This could be the most effective way to achieve this task :)

id = $(".se[style*='display:block']").attr("id");

However, it is important to consider multiple instances when using classes as selectors, as there may be several div elements that need to be accessed. In such cases, try this approach instead:

$(".se[style*='display:block']").each(function(){
    //You can perform actions on each element here
    // Use `this` as a selector, for example
    id = this.attr('id');
});

A quick note: Ensure that your selectors accurately target the desired item in terms of CSS. For instance,

style = $('element').attr('style');
will only retrieve values from the actual HTML element like <div style="display:block".

To access style values set in the CSS, utilize the appropriate selector.

http://jsfiddle.net/4jVC8/

Remember that these are distinct aspects!

Here's another filtering version:

$('div.se').filter(function() {
    return ( $(this).css('display') == 'block');
}); 

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