Can a universal selector be used to target a specific nth element and all subsequent occurrences of that element type?

As I navigate through using a data scraper, I find myself in the realm of code where my knowledge is limited. The tool I am using is free but comes with its limitations such as a crawl limit and no option to resume from the endpoint. My goal is to scrape all li elements on the page, yet the program restricts me to selecting either one or all li's at once. I am seeking advice on creating a manual selector or xpath that would enable me to start selecting from the nth-child(200) onwards. Any guidance or suggestions would be greatly appreciated!

cssweb-scrapingxpathselectorparsehub

Answer №1

To target specific elements in a list, you can utilize the powerful :nth-child() selector and adjust the functional notation to fit your criteria. More information on this selector and its functionality can be found here.

For example, by setting it to :nth-child(n+5), you can style not only the fifth element but also all subsequent elements:

li:nth-child(n+5) {
    border: 2px solid red;
}
<p>Numbers:</p>
<ul>
    <li>1</li>
    <li>2</li>
    <li>3</li>
    <li>4</li>
    <li>5</li>
    <li>6</li>
    <li>7</li>
    <li>8</li>
    <li>9</li>
    <li>10</li>
</ul>

Answer №2

After much consideration, I have finally cracked the code. Let x and y be our known variables in this scenario:

element:nth-child(n+x)                     = Moving forward from x 
element:nth-child(-n+x)                    = Going up to x 
element:nth-child(n+x):nth-child(-n+x)     = Covering the range between x and y

Therefore, for this particular situation, the correct answer would be:

element:nth-child(n+200)

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