assisting with the transition effect using CSS3, JS, or jQuery

I am looking to alter the background-image of this particular image when transitioning to another one from my images folder, similar to this example. Below is the code that I have:

CSS

.image {
    position: relative;
    overflow: hidden;
    -webkit-transition: all 0.5s ease-out;
    -moz-transition: all 0.5s ease-out;
    transition: all 0.5s ease-out;
    opacity:1;
    filter:alpha(opacity=100);
}
.image:hover {
    opacity:0;
    filter:alpha(opacity=0);
    -moz-transform:  scale(1.00) rotate(0deg) translate(0px, 100px) skew(0deg, 0deg);
    -webkit-transform:   scale(1.00) rotate(0deg) translate(0px, 100px) skew(0deg, 0deg);
    transform: scale(1.00) rotate(0deg) translate(0px, 100px) skew(0deg, 0deg); 
    transform-origin: 0% 0%;
    background-color:#36F;
}

HTML

<div id="image_holder_1" class="image_holder">
    <img id="image_1" class="image" src="images/esu.gif" />
</div>
javascriptjqueryhtmlcss

Answer №1

If you're looking for a solution, jQuery.cycle is the way to go.

<script type="text/javascript>

    $(document).ready(function() {
        $('.image_holder').cycle({
                fx: 'fade' // choose your transition type, ex: fade, scrollUp, shuffle, etc...
        });
    });
</script>

To make this work, remove the "image" id and place your image elements inside the "image_holder" that contain links to the images you want to cycle through. Your html should resemble this:

<div id="image_holder_1" class="image_holder">
         <img src="images/esu.gif"/>
         <!-- Include other image sources here -->
</div>

If the image transition looks good with your css, use your css for the transition and skip mentioning the transition type in jQuery. Check out the available transitions provided by jQuery.cycle here.

Answer №2

Implementing the desired effect you provided within CSS would prove to be challenging due to the inability to cancel transition animations. Each animation triggered by mouse over and mouse out events in the CSS would have to fully complete before transitioning to the opposite state.

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