An object that holds CSS attributes

I am working on a function that takes an element from the page and adds CSS styles to its attribute. The argument passed to this function should ideally be an object with keys like height, minWidth, flexDirection, and so on.

function addStyle (el: HTMLElement, style: Style): void {
  for (const property in style) {
    el.style[property] = style[property]
  }
}

My issue lies in defining the type for this object. It's not practical to manually list every CSS property. I believe TypeScript should have a way to handle this automatically, but I'm unsure how to do it. This is my best attempt:

type Style = Partial<CSSStyleDeclaration>

...yet I encounter the error "

Type 'string | undefined' is not assignable to type 'string'
": TypeScript playground

This particular error can be addressed, but I'm concerned that it may indicate a mistake or confusion on my part.

Is there a standard method to define the type for an object containing CSS properties?

Answer №1

It's a bit tricky to handle situations like this in TypeScript. When dealing with properties that may or may not exist on an object, TypeScript treats both scenarios – the property existing but containing undefined, and the property not existing at all – the same way.

For instance, let's say you want to type an object that might have a property called foo which is expected to be a string. You can't simply do { foo: string } because the property might not be there. One option is to use { foo: string | undefined }. Another possibility is { foo?: string }, although it's practically the same as the previous one. Unfortunately, there isn't a way to specify that a property may or may not exist, without potentially containing undefined.

A similar dilemma arises when working with CSSStyleDeclarations which involve numerous properties. While using

Partial<CSSStyleDeclaration>
is recommended, TypeScript doesn't make a distinction between partial types with properties possibly holding undefined values and those without these properties, requiring assertions for existence.

However, there is a workaround that avoids individual value references and assertions – leveraging Object.assign:

type Style = Partial<CSSStyleDeclaration>;
function addStyle(el: HTMLElement, style: Style) {
    Object.assign(el.style, style);
}

(Also, it's worth noting that specifying function return types in TypeScript isn't necessary if the compiler can infer them automatically – minimizing code clutter is often beneficial.)

Answer №2

This solution has worked well in my experience:

Subset<Exclude<CSSStyleDeclaration,
    'length'
    | 'parentRule'
    | 'getPropertyPriority'
    | 'getPropertyValue'
    | 'item'
    | 'removeProperty'
    | 'setProperty'
    | number>>

It is worth noting that you might need to utilize Object.assign() instead of a for loop, due to TypeScript simplifying the property type to a string.

Answer №3

Utilize the non-null assertion operator specifically designed for your use case, now with an added exclamation mark!

type Style = Partial<CSSStyleDeclaration>

function addStyle (el: HTMLElement, style: Style): void {
  for (const property in style) {
    el.style[property] = style[property]!;
  }
}

You can also opt to add || '' as an alternative.

type Style = Partial<CSSStyleDeclaration>

function addStyle (el: HTMLElement, style: Style): void {
  for (const property in style) {
    el.style[property] = style[property] || '';
  }
}

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