With Jquery, my goal is to position a div outside of another div element

I need to place a div tag in a specific way, like this:

<div class="abc">
  <div class="mySlides fade">
    <img src="img_nature_wide.jpg" style="width:100%">
  </div>
<div>

Using jQuery, my goal is to position the second div above the first one within this container.

Current structure:

<div class="slideshow-container">

<div class="mySlides fade">
  <img src="img_nature_wide.jpg" style="width:100%">
</div>

<div class="mySlides fade">
  <img src="img_snow_wide.jpg" style="width:100%">
</div>

<div class="mySlides fade">
  <img src="img_mountains_wide.jpg" style="width:100%">
</div>

</div>

Desired output:

<div class="slideshow-container">

<div class="abc">
  <div class="mySlides fade">
    <img src="img_nature_wide.jpg" style="width:100%">
  </div>
<div>

<div class="mySlides fade">
  <img src="img_snow_wide.jpg" style="width:100%">
</div>

<div class="mySlides fade">
  <img src="img_mountains_wide.jpg" style="width:100%">
</div>

</div>
javascripthtmljquerycss

Answer №1

Looks like using the .wrap function would be beneficial in this case.

$(document).ready(function() {
    $("#Fistdiv" ).wrap( "<div class='abc'></div>" );
});
<script src="https://code.jquery.com/jquery-3.5.1.min.js"></script>
<div class="slideshow-container">

    <div id="Fistdiv" class="mySlides fade">
        <img src="Trys/StartMap.png" style="width:100%">
    </div>

    <div class="mySlides fade">
        <img src="Trys/StartMap.png" style="width:100%">
    </div>

    <div class="mySlides fade">
        <img src="Trys/StartMap.png" style="width:100%">
    </div>

</div>

I have included an id to specifically identify the first div.

Hopefully, this solution proves useful for you.

Answer №2

Forget about using jquery, all you need is this.parent. If this solution doesn't solve the issue, make sure to examine the scope chain thoroughly.

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