What strategies can be used to resolve the problem of image hover?

I have a unique idea for my webpage where I want to showcase a grid view of black and white images. When I hover over each image, it transforms into a colored version. Additionally, clicking on an image will not only change it to color but also add a tick mark.

To implement this feature, I utilized the following script and HTML code:

SCRIPT

$(".swap_image").live('click', function() {
if($(this).attr("class") == "swap_image") {
    this.src = this.src.replace("_blackwhite", "_color");
    $('#tick_' + $(this).attr('rel')).show();
} else {
    this.src = this.src.replace("_color", "_blackwhite");
    $('#tick_' + $(this).attr('rel')).hide();
}
$(this).toggleClass("color");
return false;});

HTML

<img id="tick_{{img.id}}" src="{{MEDIA_URL}}img/tick.png" style="position:absolute;" ><a href="#"><img rel="{{img.id}}" src="{{MEDIA_URL}}{{ img.logo_blackwhite }}" onmouseover="this.src='{{MEDIA_URL}}{{ img.logo_color }}'" onmouseout="this.src='{{MEDIA_URL}}{{ img.logo_blackwhite }}'" class="swap_image" /></a>

The current setup works perfectly fine, however, there is an issue with the mouseout function causing the images to revert back to black and white once the mouse moves away.

Are there any alternative ideas or solutions to resolve this problem effectively? Thank you in advance.

Answer №1

One idea is to assign a new class to the image upon clicking, and then in the mouseout function, check if that class exists to determine whether or not to revert the image back to black and white.

Answer №2

Whenever you interact with the image, make sure to leave a noticeable mark. For example, try altering the image's class. Then, in your mouseout function, ensure that the particular class is present on the image. If it is, no action is needed; if not, consider changing the color of the image.

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