Illustrated in the example below
My objective is to establish a yellow backdrop for a specific row in my table. However, when I utilize the code snippet below
<table class="table table-bordered table-striped">
The row's background doesn't reflect my desired color due to the pre-existing classes. Is there a method by which I can preserve the classes while ensuring that my chosen color remains dominant?
The row appears to be yellow, but in reality, the cells inside have a #f9f9f9 color that obscures the row's background.
You must adjust your selector to target the cells within the row instead of the row itself. Additionally, you should enhance the specificity of the selector as the current ones are more specific than what is currently being used.
The reason for this occurrence is due to CSS specificity. The selector table.table-striped tr holds more specificity compared to table tr, resulting in it overriding the latter. It is advisable to minimize the use of !important and instead concentrate on enhancing the specificity of your selectors. Therefore, in your scenario, adjust the selector as follows:
table.table-striped tr.zebraHover td {
background-color: #FFFACD;
}
Revise your CSS styling
tr.highlightedRow td {
background-color: #FFFACD !important;
}
I am aware that this code is not ideal. If you have a better approach, feel free to share it in the comments section. I'm keen on learning a more efficient solution!
Convert the class into an id.
CSS:
#stripedHighlight td{
background-color: #FFFACD;
}
HTML
<tr id="stripedHighlight">
<td>1</td>
<td>User1</td>
<td><a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="087d7b6d7a39486f65696164226c6062">[email protected]</a></td>
<td><a class="btn btn-danger" href="#">Deactivate</a></td>
</tr>
tr.zebraHover,
.table-striped tbody tr:nth-child(2n+1).zebraHover td
{
background-color: #FFFACD;
}
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