What is the most efficient way to retrieve the two smallest numbers using jQuery?

I am trying to find the two smallest numbers out of a set of three, and then I want to display them on the screen. In PHP, we usually use echo to display values on the screen. However, with this code snippet, I am only able to get one smallest value instead of both. How can I modify it to display both of the smallest numbers on the web page?

<script type="text/javascript">
  var a = 5;
  var b = 4;
  var c = 6;
  var d = Math.min(a,b,c);
</script>

Therefore, the expected output should be "First smallest: 4" and "Second smallest: 5".

I aim to store these first and second lowest values in different variables like var first = 4 and var second = 5, and then display them using PHP code <?php echo $first;?> and <?php echo $second ; ?>.

Answer №1

let x = 4; // select the minimum number
let numbers = [4,6,7,9], result=[];
let minNum;
for(i=0;i< x;i++){
    minNum = Math.min.apply(Math,numbers); 
    result.push(minNum);
    numbers.splice(numbers.indexOf(minNum), 1);
}
alert(result);

JS Bin link

Answer №2

Here is a simple way to achieve this using pure JavaScript:

Start by sorting the array of numbers and then iterate over it to find the required values

function FindLowestAndSecondLowest(arr)
{
  arr.sort(function(a, b) {
    return a - b;
  });
  
  var uniqueValues = [arr[0]];
  var result = [];
  
  for(var i=1; i < arr.length; i++)
  {
    if(arr[i-1] !== arr[i])
    {
      uniqueValues.push(arr[i]);
    }
  }
  
  result.push("Lowest: " + uniqueValues[0], "Second Lowest: " + uniqueValues[1]);

  return result.join(' & ');
}

document.write(FindLowestAndSecondLowest([4, 5, 6]));

Answer №3

To locate the highest value in an array and remove it, follow these steps:

var x = 10, y = 15, z = 8;
var arr = [];
arr.push(x, y, z);
var highest = Math.max(x, y, z);
arr.splice(arr.indexOf(highest), 1);
var low1 = arr[0];
var low2 = arr[1];

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