Currently undertaking the task of refining over 10,000 lines of CSS code. Instead of manually converting line by line, I aim to transform from this:
-webkit-transition: .1s linear all;
-moz-transition: .1s linear all;
transition: .1s linear all;
to this:
.transition(.1s linear all);
I am seeking a way to expedite this process using regex. Any suggestions would be greatly appreciated!
Thank you in advance!
Determining the extent of data variability will influence the approach, however, the following serves as a solid foundation:
/(?:\s*(?:-(?:webkit|moz)-)?transition:\s*\.1s linear all;\n)+/
For adaptable values, adjust the pattern to suit the characteristics of your data.
To improve the conversion process, consider utilizing a CSS parser to interpret the CSS and then create custom methods to generate LESS code. Here is a Java-based parser that can help with this.
It may be more efficient to retain the existing CSS and only implement new stylesheets using LESS rather than attempting to convert all existing CSS files.
Attempting to use regex for this task may not be ideal, as the CSS syntax must adhere to specific rules which might not align with over 10000 lines of code.
Alternatively, you could explore using this online converter, although it may not fulfill the exact requirements you have in mind.
My initial step would be eliminating all prefixes (http://refiddle.com/2t4) followed by substituting the unprefixed ones with the mixin (http://refiddle.com/2t5).
Unsure if the text editor you're utilizing supports find and replace using regex. (I tested out these steps in Eclipse IDE)
Step 1 : Search for ".-webkit-." and substitute with nothing
Step 2 : Look for ".-moz-." and swap it with blank space
Step 3 : Find "(transition):(.*);" and switch it to ".$1($2);"
I trust this information proves beneficial.
#!/usr/bin/python
import re
with open('/tmp/example.txt') as file:
for txt in file:
result = re.match(r'(.*)(conversion):\s*(.*);', txt)
if result:
print(".%s(%s);" % (result.group(2), result.group(3)))
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