What is the best way to use jQuery to smoothly transition to the next image in the lineup?

I have a requirement to create a slideshow of images, where each image fades out before the next one fades in. It seems like a straightforward task.

<ul class="nav fading">
  <li><?= anchor("#","Supported by",array("class" => "footer-heading disabled")) ?></li>
  <li><?= img("assets/img/1.png") ?></li>
  <li><?= img("assets/img/2.png") ?></li>
</ul>

Here is my current code:

$(document).ready(function(){
    $(".fading img").hide(); //start with hiding all images
    $(".fading img:first").fadeIn(4000); //fade in the first image
    $(".fading img:first").fadeOut(4000,function(){
        $(this).parent().next().fadeIn(4000); //fade in the next image after previous one fades out
    });
});

I have successfully tested fading the same image back in after it has faded out:

$(document).ready(function(){
        $(".fading img").hide(); 
        $(".fading img:first").fadeIn(4000);
        $(".fading img:first").fadeOut(4000,function(){
            $(this).fadeIn(4000);
        });
    });

However, I encounter an issue when attempting to fade in the subsequent image in the sequence.

Answer №1

If you want to locate an <img> relative to another, you need to navigate back down a specified "generation" using either the .find() or .children() methods after moving up with .parent():

$(this)             // refers to the current <img> element
    .parent()       // go up to its parent <li> (second in the <ul>)
    .next()         // move to the last <li>
    .find('img')    // select the <img> within the last <li>
    .fadeIn(4000);

Otherwise, the original code was targeting and trying to .fadeIn() the <li> element instead of affecting the underlying <img>.

$(this).parent().next().fadeIn(4000);

Answer №2

Here is my recommendation

Substitute the given text with the following

$(this).parent().next().fadeIn(4000);

And switch it to this

$(this).parent().next().find('img').fadeIn(4000);

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