https://i.sstatic.net/S4LPu.png
Hi there, I'm facing a challenge with a project where my client wants to implement this orange border in react native. Unfortunately, CSS is not my strong suit. Can anyone please help me figure out how to achieve this effect?
By tilting a parent element and counter tilting its child elements, you can achieve the desired effect using just a few lines of CSS:
/* Solution */
.item { transform: skew(-15deg) } /* tilt */
.item .content { transform: skew( 15deg) } /* untilt */
/* Additional styling for visual appeal */
.wrapper { display: flex; gap: 0.5rem }
.item { border: 2px solid orange }
.item .content { padding: 0.5rem 1rem }
.item:hover { cursor: pointer; background-color: hsl(0,0%,96%); border-color: black }<div class="wrapper">
<div class="item">
<div class="content">some content</div>
</div>
<div class="item">
<div class="content">some content</div>
</div>
<div class="item">
<div class="content">some content</div>
</div>
</div>To achieve a skewed effect in CSS, you can utilize the transform skew function. One way to apply this is by using an after pseudo element to prevent distorting the content of the div. Here's an example:
.losange {
position: relative;
width: 100px;
padding: 10px;
}
.losange:after{
content: '';
display: block;
position: absolute;
top: 0;
right: 0;
bottom: 0;
left: 0;
height: 100%;
width: 100%;
border: 2px solid orange;
transform: skew(-0.25rad);
pointer-events: none;
}<div class="losange">test</div>EDIT: If you also want to skew the background color, you can achieve this by adding it to the after pseudo element and setting the z-index to -1 to place it behind the content of the losange.
.losange {
position: relative;
width: 100px;
padding: 10px;
}
.losange:after{
content: '';
display: block;
position: absolute;
top: 0;
right: 0;
bottom: 0;
left: 0;
height: 100%;
width: 100%;
border: 2px solid orange;
transform: skew(-0.25rad);
pointer-events: none;
background-color: #eeeeee;
z-index: -1;
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