Is there a way to show an image in a larger div when clicked on another div with a smaller size?
Despite multiple attempts and various approaches, I have been unsuccessful in achieving this task. Thus, after hours of effort, I decided to seek help here. Below is my code snippet:
I am looking to showcase an image that is clicked in a smaller slide within a div named largerimage.
$(document).ready(function(){
$("img").click(function()
{
$(".largerimage").show($this);
});
});
Yes, I believe this solution will work.
$("img").click(function(){
$img = $(this).clone();
$(".largerimage").show().html($img.removeAttr('width'));
});<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<img width="100" src="http://dummyimage.com/300x200/000/fff"/>
<div class="largerimage"></div>Give this a try for potential assistance
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
$('img').click(function(){
$largeimage = $(this).clone().css({height:"300", width:"300"});
$(".largerimage").html($largeimage);
});
});
</script>
</head>
<body>
<img width="50" src="C:\Users\buffer\Pictures\a.jpg" />
<img width="100" src="C:\Users\buffer\Pictures\b.png" />
<img width="200" src="C:\Users\buffer\Pictures\c.png"/>
<div class="largerimage"></div>
</body>
</html>
Showcasing three images of differing widths within a larger div with fixed dimensions.
Here is a functioning code snippet:
$(document).ready(function(){
var height1 = $("div.first").height();
var width1 = $("div.first").width();
var area1 = height1*width1;
var height2 = $("div.second").height();
var width2 = $("div.second").width();
var area2 = height2*width2;
if (area1>area2) {
$("div.first").click(function(){
$("img").show();
});
}
if (area2>area1) {
$("div.second").click(function(){
$("img").show();
});
}
});
Feel free to test it out on this fiddle.
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