Ways to retrieve all elements following a chosen element

Is there a way to include the last element too?

$('div.current').nextUntil("div:last").css("color", "blue");
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<div>First</div>
<div>Second</div>
<div class="current">Third</div>
<div>Fourth</div>
<div>Fifth</div>
<div>Sixth</div>
<div>Seventh</div>

Answer №1

If you want to target elements after a specific element, you can use the nextAll() method like this:

$('span.active').nextAll().addClass('highlight');
.highlight { background-color: yellow; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<div>Apple</div>
<div>Orange</div>
<span class="active">Banana</span>
<p>Grapes</p>
<p>Mango</p>

Answer №2

To combine the andSelf method with the next() method can be a helpful strategy.

The andSelf method appends the previous set of elements on the stack to the current set.

$('div.current').nextUntil("div:last").andSelf().next().css("color", "blue");
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<div>First</div>
<div>Second</div>
<div class="current">Third</div>
<div>Fourth</div>
<div>Fifth</div>
<div>Sixth</div>
<div>Seventh</div>

Answer №3

To target specific elements in your HTML, you can utilize the general sibling combinator with the symbol ~

$('div.current ~ div').css("color", "blue");
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<div>First</div>
<div>Second</div>
<div class="current">Third</div>
<div>Fourth</div>
<div>Fifth</div>
<div>Sixth</div>
<div>Seventh</div>

Answer №4

To select all the next following elements, you can simply omit any parameter inside the nextUntil() function.

Another option is to use the nextAll() method.

$('div.current').nextUntil().css("color", "blue");
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<div>First</div>
<div>Second</div>
<div class="current">Third</div>
<div>Fourth</div>
<div>Fifth</div>
<div>Sixth</div>
<div>Seventh</div>

Answer №5

Opt for using the nextAll jQuery method over nextUntil.

$('div.current').nextAll().css("color", "blue");
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<div>First</div>
<div>Second</div>
<div class="current">Third</div>
<div>Fourth</div>
<div>Fifth</div>
<div>Sixth</div>
<div>Seventh</div>

Answer №6

Check out this snippet to achieve the desired functionality in your code!

$('div.current').nextUntil("html").css("color", "blue");
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<div>First</div>
<div>Second</div>
<div class="current">Third</div>
<div>Fourth</div>
<div>Fifth</div>
<div>Sixth</div>
<div>Seventh</div>

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