Ways to deactivate a button using CSS

I need to use Javascript to disable a link based on its id. By default, the link is invisible. I will only enable the link when the specific id value comes from the backend.

HTML

<li id="viewroleId" style="display: none;">
    <a href="viewrole"><spring:message code="label.viewrole" /></a>
</li>

Javascript:-

if (key == 1) {
    var id = value;
    var div = document.getElementById(id);

    if(div != null){
        if (div.style.display == 'none' || div.style.display == '') {
            // This line will make the link visible
            div.style.display = 'block';
        }
    }
}

In the above Javascript code, I am focusing on making the link visible. Now, how can I both display and disable the link using CSS instead?

javascripthtmlcssangularjs

Answer №1

To begin, establish a CSS rule similar to the following:

.disabled {
    display: block !important; /* Overriding the inline style with important flag */
    pointer-events: none; /* Disabling element interaction */
    color: #ccc; /* Changing text color to gray to indicate disabled state */
}

Next, in your JavaScript code, assign the class disabled to the desired element like this:

if (key == 1) {
    var id = value;
    var div = document.getElementById(id);

    if(div != null){
        if (div.className.indexOf('disabled') === -1) {
            // Element will be visible but disabled
            div.className += ' disabled';
        }
    }
}

Answer №2

For Angular-based apps, it's recommended to utilize ng-if as it follows the "natural way."

<a ng-if="true" href="yourlink.html">Link<a/>
<a ng-if="!true" href="#">Link<a/>

It's advisable to avoid trying to override the browser's native implementation for links.

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