Using JQuery to switch out images that do not have an ID or class assigned

Currently, I am using a Google Chrome Extension to apply an external theme to a website. Unfortunately, the logo on the site does not have an ID or class that can be used to call it. I am searching for a solution to replace it with a different image. My initial thought is to locate the image based on its size, but I am unsure of the next steps to take.

Answer №1

Assuming it is located inside a <div id="something">, you can target it using the following snippet:

$("#something img:first").attr('src', 'http://new.src/img.gif');

Answer №3

Start by selecting a nearby element.

For example, if it is the third child of an element with the id example:

$("#example :nth-child(3)").attr('src', '...');

If the parent element does not have an ID, use the direct child selector. For instance, given the following HTML:

<div id="myDiv">
    <div>blah</div>
    <div><img src="..."/></div>
</div>

Your selector should be:

$("#myDiv > div:nth-child(2) > img");

Answer №4

To change the source of a specific image using jQuery, you can use the following syntax:

$("img:eq(1)").attr("src", "file.png");

Keep in mind that the index for selecting elements with `eq()` is zero-based. As mentioned by waitinforatrain below, this aligns with how JavaScript arrays are indexed. According to the API documentation:

JavaScript arrays start counting from 0, hence the selectors in jQuery follow the same pattern. So when you use $('.myclass:eq(1)'), it will actually target the second element with the class myclass, not the first one. On the other hand, :nth-child(n) uses 1-based indexing as per CSS specifications.

For a more detailed explanation on the :eq selector, refer to the official JQuery API documentation here.

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