Using jQuery to swap an image with a div element and then using the image as the

I have a collection of images in a div, like so:

<div class="image-container">
    <img width="174" height="174" src="http://mysite.com/images/portfolio/p1.jpg" class="image-style" typeof="foaf:Image">
    <img width="174" height="174" src="http://mysite.com/images/portfolio/p2.jpg" class="image-style" typeof="foaf:Image">
    <img width="174" height="174" src="http://mysite.com/images/portfolio/p3.jpg" class="image-style" typeof="foaf:Image">
    <img width="174" height="174" src="http://mysite.com/images/portfolio/p4.jpg" class="image-style" typeof="foaf:Image">
</div>

I would like to use jQuery to convert each image into a div and set the image as a background image, similar to this structure:

<div class="image-container">
        <div style="background-image:url(http://mysite.com/images/portfolio/p1.jpg)"><span>image</span></div>
        <div style="background-image:url(http://mysite.com/images/portfolio/p2.jpg)"><span>image</span></div>
        <div style="background-image:url(http://mysite.com/images/portfolio/p3.jpg)"><span>image</span></div>
        <div style="background-image:url(http://mysite.com/images/portfolio/p4.jpg)"><span>image</span></div>
</div>

While I can achieve this for one image, I am unsure of the best method to iterate through all the images within my parent div (image-container) and make the necessary conversions.

Any assistance on this matter would be greatly appreciated. C

jqueryhtmlcss

Answer №1

To replace an image with a div element and span using the replaceWith method, you can use the following code:

$('.image-container img').replaceWith(function(i, v){
    return $('<div/>', {
        style: 'background-image: url('+this.src+')',
        html: '<span>image</span>'
    })
})

Visit this link for more details

Answer №2

Feel free to give this a try: :) http://jsfiddle.net/x5HhV/

jquery change background-image

Hopefully, this solution is helpful :)

Check out the API reference here: http://api.jquery.com/replaceWith/

code

$("div.image-container > img").each(function(index) {
    index = index + 1
    $(this).replaceWith('<div style="background-image:url(http://mysite.com/images/portfolio/p' + index + '.jpg)"><span>image</span></div>');

    alert(index + ' HTML has been updated to => ' + $("div.image-container").html());

});

​

Answer №3

Well, it's always important to go through each step carefully

$('div.image-container img').each( function(i,o){
    // This is a custom function for handling img tags
    // You can easily access the current img tag using $(o), like so:
    $(o).replaceWith('<div style="background:url(' + $(o).attr('src')+')"><span>image</span></div>');
});

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