Using JavaScript to display a div based on the value of a checkbox by manipulating the style display attribute

Recently, I put together a web form using ASP.NET MVC.

After some trial and error, I managed to configure my View so that it displays a checkbox that reveals a specific div when clicked. Below is the core JavaScript code that makes this possible:

$('div.schedule .input_control').click(function () {
  var $target = $(this).closest('div').find('.showSchedule');
   if (this.checked) {
      $target.show();
   } else {
      if (confirm("Are you sure you want to exclude this schedule?") == true) {
        $target.hide();
        $(':hidden').not("input[name=__RequestVerificationToken]").val('');
      } else {
        $(this).prop("checked", true);
      }
   }
});

Here's a snippet of the HTML containing the checkbox and the hidden/shown div:

<div class="schedule">
   @Html.CheckBox("schedule", false, new { @class = "input_control" })
   <div style="display: none" class="showSchedule">
      //form fields
   </div>
</div>

The functionality works flawlessly - the div appears or disappears based on the state of the checkbox, while the confirmation message functions as intended.

However, a challenge arises when there are validation errors and the form page reloads – the div remains hidden despite the checkbox being checked!

How can this inconsistency be rectified, ensuring the div always reflects the checkbox status? It’s crucial for situations where edits are made, but the checkbox stays ticked yet the div remains concealed.

This discrepancy likely stems from the default "display: none" setting of the div.

What would be a more reliable approach to address this issue?

Answer №1

Include a feature to determine whether the checkbox is selected upon page load. If it is selected, display the corresponding div; otherwise, hide it.

$(document).ready(function () {
    var $checkBox = $('div.schedule .checkbox_input:checked');
    var $visibleDiv = $checkBox.closest('div').find('.showSchedule');
    $visibleDiv.show();
});

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