Use jQuery to locate the nearest elements

Currently seeking a way to locate and choose the 5 nearest "li" elements (two, three, four, five, and six) with the class "active". Any suggestions?

<li class="one">Hello</li>
<li class="two">Hello</li>
<li class="three">Hello</li>
<li class="four active">Hello</li>
<li class="five">Hello</li>
<li class="six">Hello</li>
<li class="seven">Hello</li>
<li class="eight">Hello</li>

Appreciate the assistance :)

Answer №1

To find the index and slice elements, utilize the index and slice methods:

let $listItems = $('li');
let index = $listItems.filter('.active').index(); 
if ( index-2 < 0 ) index = 0;

$listItems.slice(index-2, index+3);

http://jsfiddle.net/abcdef/

Answer №2

Give this a shot:

let $active = ​$( ".active" ),
    $siblings = $active.​​​​​​siblings().andSelf(),
    index = $siblings.index( $active ),
    startIndex = index < 2 ? 0 
    : index + 5 > $siblings.length ? $siblings.length - 5 : index - 2;
    $collection = $siblings.slice( startIndex, startIndex + 5 );

$collection contains the selected elements.

Answer №3

While it may not be the most aesthetically pleasing code sample, it gets the job done :)

var activeItem = $('li.active');

activeItem.prev('li').addClass('active').prev('li').addClass('active');
activeItem.next('li').addClass('active').next('li').addClass('active');

Within this snippet, I am harnessing the power of jQuery's chaining feature. This means that the functions I've employed return the object itself that the action was performed on. So, the addClass() function returns the item we added the class to, allowing us to link functions together.

Witness it in action here

For further information:

Answer №4

When in need of obtaining 5 outcomes:

const totalItems = $('li').length;
let startingPoint = $('.active').index() - 2;
startingPoint = startingPoint + 5 > totalItems ? totalItems - 6 : startingPoint;
startingPoint = startingPoint < 0 ? 0 : startingPoint;
const resultItems = $('li').slice(startingPoint, startingPoint + 5);

This set of instructions should fulfill the requirement.

Answer №5

A concise answer in one line

$('li.active').prevAll().andSelf().slice(-3).add('li.active + *').add('li.active + * + *').css('color','red');

Explanation: Retrieve elements preceding the active item using the prevAll method, include the active item itself, and only select the last 3 elements using the slice function. Include elements after the li.active using the add method with the special + selector

View demo

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