Upon the initial sliding down of a div, the child elements within it will be displayed using JQuery

I am in the process of developing a website using JQuery, and I encountered an issue with a signup bar. When I click a button, I want the bar to slide down smoothly. However, on the initial click, the signup form appears before the background color of the containing div slides into view. This discrepancy is quite noticeable. The code snippet below is what I used to ensure that the form slides up first and then down last:

            if (signupBarDown) {
                $signup.slideUp();
                $login.slideUp();
            }

            $signupOrLoginDiv.slideToggle(400);

            if (!signupBarDown) {
                $signup.slideDown();
                $login.slideDown();
            }

            signupBarDown = !signupBarDown;

Although this code works perfectly after the first slide up/down, I cannot figure out why it behaves unexpectedly at the beginning.

The forms are positioned absolutely, which led me to write this script. But for some reason, this positioning seems to be causing the issue. Additionally, the 'signupBarDown' variable initializes as false. I attempted changing the positioning to fixed, thinking it might resolve the problem since absolute positioning had affected the script previously, but the outcome remains unchanged.

Answer №1

The reason for this issue has been identified. In order to prevent this from happening, it is necessary to hide it from the beginning of the code or by default in the CSS. If not done so, even though it takes 400ms to open, the website registers it as open before it is fully opened. As a result, the forms are displayed because the parent element is no longer hidden. Adding $signup.hide() and $login.hide at the beginning of the $(document).ready function resolves this issue. This ensures that although the parent element is visible, the child element remains hidden. Subsequently, once this process is complete, the form is displayed correctly.

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