Updating the CSS: Using jQuery to modify the display property to none

I am facing an issue with displaying an element that is defined as display:none in CSS. I tried to use the .show() function in jQuery, but it's not working as expected. Here's the code snippet:

CSS

.element {
  position: absolute;
  display: none;
  left: 0;
  top: 0;
}

HTML

<div class="element">Some content here</div>
<div class="element">Some content here</div>

jQuery

var c = $('.element');

c.each(function () {
  c.css({
    'left': dleft + 'px'
  });

  c.css({
    'top': dtop + 'px'
  });

  c.setTimeout(function () {
    c.show(1000);
  }, sduration);

I have checked all variables and even set default values for them, yet the element remains hidden after the timeout period.

javascriptjqueryhtmlcsssettimeout

Answer №1

It looks like there are a couple of issues within the code snippet provided. One issue is that the .each() loop is not properly closed. Additionally, it seems that setTimeout is being used as a global function. Make sure to address these concerns.


var dleft = 40;
var dtop = 40;
var sduration = 1000;
var c = $('.element');

c.each(function() {
    c.css({
        'left': dleft + 'px',
        'top': dtop + 'px'
    });
});
setTimeout(function() {
    c.show(1000);
}, sduration);​

For reference, please see this FIDDLE

Answer №2

setTimeout is a built-in function that operates globally.

var box = $('.box');

box.each(function () {
  box.css({ 'left': positionLeft + 'px', 'top': positionTop + 'px' });

  setTimeout(function () {
    box.fadeIn(500);
  }, duration);
});

Check out the demo: http://example.com/demo123

Answer №3

If you find yourself in need of postponing the appearance of elements, you can utilize jQuery's .delay() method.

e.each(function() {
    e.css({
        'left': newLeft + 'px',
        'top': newTop + 'px'
    });
});

e.delay(500).show();

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