Troubleshooting jQuery Selector and CSS Issues

Issue 1: I am facing a problem with assigning content to a variable referenced by className, which includes a string in back and an HTML string in link.

var back = "test";
var className = "link1";
var link1 = '<div id="back" class="gohome"></div><div class="link3"></div><div class="link4"></div>';

It seems like the following code is not working as expected

$(className) = className + back;

Issue 2: The code below is not updating the CSS of prevClass variable.

       $('[id*="back"]').each(function(){
            $('.' + prevClass).css({'left': '-123px'});
            $('.' + prevClass).css({'top': '430px'});
            $('.' + prevClass).css({'width': '123px'});
            $('.' + prevClass).css({'height': '44px'});

<script type="text/javascript">

    var back = "";
    var prevClass = "start"
    var className = "Broken";

    start = '<div id="back" class="gohome"></div><div class="link1"></div><div class="link2"></div>';
    gohome = '<div class="gohome"></div><div class="start"></div>';
    link1 = '<div id="back" class="gohome"></div><div class="link3"></div><div class="link4"></div>';
    ...
    // Include rest of the script code here
jquerycss

Answer №1

When tackling the first issue, it is essential to make more strategic selections and updates. Since classname is a class name, the optimal approach would be:

$('.' + className)

(Similar to what you have successfully implemented for problem #2)

If the intention is to update the content (with back):

$('.' + className).html(back);

Regarding problem #2, there seems to be some ambiguity.

Firstly, is #back already present in the DOM? This will not function correctly with your link1 variable. Secondly, what is the intended purpose of prevClass?

Answer №2

Does your className belong to an anchor element? Here is a possible solution:

$('.className').attr('href', link1 +'/'+ back);

Answer №3

Solution for Issue 1:

$(className) = className + back;

This code snippet simply assigns the value link1test to the variable $(className).

For example: $(className) = "link1test"

If you need to update the content of the variable className with the content from back, you should use the following:

$('.' + className).html(back);

Solution for Issue 2:

It seems like the selector might be incorrect. If you are trying to select a single element with the id back and then adjust the css of its children with the class prevClass, you can try the following approach:

   $('#back').each(function(){
        $('.' + prevClass).css({'left': '-123px'});
        $('.' + prevClass).css({'top': '430px'});
        $('.' + prevClass).css({'width': '123px'});
        $('.' + prevClass).css({'height': '44px'});
    });

Answer №4

If you're looking to streamline your jQuery code, using the following syntax can simplify selecting ID's:

$('#back')

It's unclear what you intend to achieve with the asterisk (*) preceding the equal sign.

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