Troubleshooting: Issue with changing the CSS of a div from display:none to display:block using jQuery

I have a scenario where the content of a div is dynamically changed based on checkbox values. For most options, the div displays simple text, but for one specific option, it should display another div (referred to as childDiv).

To achieve this functionality, I am toggling the visibility of the childDiv using jQuery's css() method. When any of the regular options are clicked, I hide the childDiv by setting its CSS property to display: none. Conversely, when the exception option is selected, I show the childDiv by changing its CSS to display: block.

The issue I'm facing is that although the childDiv hides correctly when switching between checkbox options, it fails to reappear when I want it to be visible again.

You can view the demo in this fiddle: http://jsfiddle.net/sandeepy02/jLgyp/

Here is the relevant code snippet:

<div class="switch switch-three candy blue" id="reachout">
    <input name="reachout" type="radio" id="tab-41" value="1" checked="checked"/>
        <label for="tab-41">Experience</label>
    <input name="reachout" type="radio" id="tab-42" value="2"/>
        <label for="tab-42">Contact Us</label>
    <input name="reachout" type="radio" id="tab-43" value="3"/>
        <label for="tab-43">Why?</label>
    <div id="test1234">
        <div id="test12345">
            Option Start
        </div>
    </div>
    <span class="slide-button"></span>
</div>

And the accompanying JavaScript:

jQuery("input[name='reachout']", jQuery('#reachout')).change(function(e) {
    if(jQuery(this).val()=="1") {
        jQuery("#test1234").html("");
        jQuery("#test12345").css("display","block");
    }
    if(jQuery(this).val()=="2") {
        jQuery("#test1234").html("Option 2");
        jQuery("#test12345").css("display","none");
    }
    if(jQuery(this).val()=="3") {
        jQuery("#test1234").html("Option 3");
        jQuery("#test12345").css("display","none");
    }
});

In an attempt to resolve the issue, I also experimented with adding the following styles to the childDiv after setting its display to block:

jQuery("#test12345").css('position', 'absolute');
jQuery("#test12345").css('z-index', 3000);

However, this did not yield the desired outcome. Any insights or suggestions would be greatly appreciated.

Thank you.

jquerycss

Answer №1

By setting the inner HTML of its parent, you are essentially replacing the entire div element. Thus, attempting to display a non-existent div.

Answer №2

Identify your issue:

The element jQuery("#test1234") is the parent of jQuery("#test12345") and what you are doing is replacing its HTML with these lines of code:

jQuery("#test1234").html("");
jQuery("#test1234").html("Option 2");
jQuery("#test1234").html("Option 3");

Prior to running this script, the original HTML structure looked like this:

           <div id="test1234">
                <div id="test12345">
                    Option Start
                </div>
            </div>

After executing your scripts, it now appears as follows:

using jQuery("#test1234").html(""); results in:

           <div id="test1234">

            </div>

employing 

jQuery("#test1234").html("Option 2");
generates:

           <div id="test1234">
                Option 2
            </div>

and utilizing 

jQuery("#test1234").html("Option 2");
yields:

           <div id="test1234">
                Option 3
            </div>

Therefore, you are setting display : block for an element that no longer exists in the DOM after the script runs.

Answer №3

Just a simple tweak in jQuery!!

jQuery("input[name='updateinfo']",jQuery('#updateinfo')).change(
                function(e)
                {                   
                    if(jQuery(this).val()=="1") 
                    {
            --> modification in this line         jQuery("#update123").html("Update Start");
                        jQuery("#update12345").css('position', 'relative');
                        jQuery("#update12345").css("display","inline-block");
                        jQuery("#update12345").css('z-index', 2000);
                    }
                    if(jQuery(this).val()=="2") 
                    {
                        jQuery("#update123").html("Update 2");
                        jQuery("#update12345").hide();
                    }
                    if(jQuery(this).val()=="3") 
                    {
                        jQuery("#update123").html("Update 3");
                        jQuery("#update12345").hide();
                    }
                });

Answer №4

Following Andrew's suggestion, I made the decision to separate the div elements rather than using a parent-child structure.

After making this adjustment, the functionality now operates exactly as I had intended.

The revised code is as follows:

<div class="switch switch-three candy blue" id="reachout">
                        <input name="reachout" type="radio" id="tab-41" value="1" checked="checked"/>
                            <label for="tab-41">Experience</label>
                        <input name="reachout" type="radio" id="tab-42" value="2"/>
                            <label for="tab-42">Contact Us</label>
                        <input name="reachout" type="radio" id="tab-43" value="3"/>
                            <label for="tab-43">Why?</label>
                        <div id="test1234">
                        </div>
                            <div id="test12345">
                                Option Start
                            </div>
                        <span class="slide-button"></span>
                    </div>

Additionally, the JavaScript function was updated to:

         jQuery("input[name='reachout']",jQuery('#reachout')).change(
            function(e)
            {                   
                if(jQuery(this).val()=="1") 
                {
                    jQuery("#test1234").hide();
                    jQuery("#test12345").show();
                }
                if(jQuery(this).val()=="2") 
                {
                    jQuery("#test1234").html("Option 2");
                    jQuery("#test1234").show();
                    jQuery("#test12345").hide();
                }
                if(jQuery(this).val()=="3") 
                {
                    jQuery("#test1234").html("Option 3");
                    jQuery("#test1234").show();
                    jQuery("#test12345").hide();
                }
            });

Answer №5

Does your identification match?

Clearing the content of element "#test1234" using jQuery.
Displaying element "#test12345" by setting its CSS property to block.

Answer №6

To make it work, follow these steps:

// Replace xxx with your specific div id
$('#xxx').hide();
$('#xxx').show();

By doing this, you should see the desired results.

Answer №7

I have made adjustments to your code based on some suggestions, and it should be functioning correctly now.

http://jsfiddle.net/jquery4u/nPMvV/

(function ($) {
    $("input[name='update']").on('change', function (e) {
        var value = $(this).val();
        console.log(value);

        // storing frequently used elements in variables
        var $element1 = $("#element1"),
            $element2 = $("#element2");

        // using a switch statement for cleaner code
        switch (value) {
            case "1":
                $element1.html("Selection 1");
                $element2.show();
                break;
            case "2":
                $element1.html("Selection 2");
                $element2.hide();
                break;
            case "3":
                $element1.html("Selection 3");
                $element2.hide();
                break;
        }
    });
})(jQuery);

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