Top method to gather all necessary inputs

I am dealing with a form that contains several required fields. You can find an example here

    <div class="form-group">
            <label class="col-md-3 control-label" for="mpassword">Password<span class="required">* </span></label>
            <div class="col-md-3">
                <input type="password" id="mpassword" name="mpassword" class="form-control" placeholder="Enter password"/> 
            </div> 
        </div>
        <div class="form-group">
            <label class="col-md-3 control-label" for="memail">Email <span class="required">* </span></label>
            <div class="col-md-3">
                <input type="email" id="memail" name="memail" class="form-control" placeholder="Enter email"/> 
            </div> 
        </div>
        <div class="form-group">
            <label class="col-md-3 control-label" for="mname">Full name<span class="required">* </span></label>
            <div class="col-md-3">
                <input type="text" id="mname" name="mname" class="form-control" placeholder="Enter name" value="MyName"/> 
            </div> 
        </div> 
       <div class="form-group">
            <label class="col-md-3 control-label" for="mname">Nick name</label>
            <div class="col-md-3">
                <input type="text" id="mname" name="mname" class="form-control" placeholder="Enter nickname"/> 
            </div> 
        </div>

I am struggling to identify the correct method for retrieving all the required fields since they do not have a specific "required" attribute or class. The only indicator of required fields is the presence of the "required" class in their labels, indicating "this input is required"

javascriptjqueryhtmlcssvalidation

Answer №1

To efficiently select the labels and retrieve the corresponding inputs using the for attribute, you can use the following jQuery code:

$('label:has(.required)').map(function() {
    return $('#' + $(this).attr('for'));
});

It is worth noting that two form elements share the same name.

Answer №2

$('.mandatory').next().find('input').each(function() {
  // manipulate elements
});

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