Tips for controlling HTML elements using JavaScript

I'm currently working on implementing a mouse-over scale effect for an HTML image. I chose to use JavaScript for this task because I need the ability to manipulate multiple elements in different ways simply by hovering over one element. Below is the JavaScript code that targets the element named "logoF" for manipulation:

$( document ).ready(function() {

var logoF = document.getElementById("#logoF");

logoF.onmouseover=function(){
    logoF.style.webkitTransform= "scale(0.8)";
    logoF.style.msTransform= "scale(0.8)";
    logoF.style.transform= "scale(0.8)";
};

});

For some reason, this code isn't producing the desired effect. I would greatly appreciate any insights or suggestions on what might be causing this issue.

Answer №1

To correctly select the element with id "logoF" in JavaScript, you should not include the "#" inside the document.getElementById function like this:

var logoF = document.getElementById("logoF");

SNIPPET

$(document).ready(function() {

  var logoF = document.getElementById("logoF");

  logoF.onmouseover = function() {
    logoF.style.webkitTransform = "scale(0.8)";
    logoF.style.msTransform = "scale(0.8)";
    logoF.style.transform = "scale(0.8)";
  };

});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<img src="https://pbs.twimg.com/profile_images/616542814319415296/McCTpH_E.jpg" id="logoF" />

Answer №2

It seems like your selector may be incorrect, which could be causing the issue.

Instead of using

var logoF = document.getElementById("#logoF");

Consider using (without the "#")

var logoF = document.getElementById("logoF");

Answer №3

Aside from providing responses, here is a code snippet to toggle image scaling on mouseover and mouseout events:

$(document).on('mouseover mouseout', '#logo', function(){
  $('img').toggleClass('scaled')
});
img {
  max-width: 100%;
  transition: 1s;
}
#logo {
  width: 300px;
  overflow: hidden;
}
.scaled {
  transform: scale(2);
  transition: 1s;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="logo">
<img src="http://www.2fons.ru/pic/201406/1920x1080/2fons.ru-21593.jpg">
</div>

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