The lesser than sign selector

Here is the code snippet that I am currently working with:

$(function() {
    $('li:lt(5)').css("background", "red");
});
<script src="https://code.jquery.com/jquery-1.10.2.js"></script>

<div id="listes">
    <ul id="ul1">
        <li>
            Element de liste 1
            <ul id="ul2">
                <li>Enfant 1</li>
                <li>Enfant 2</li>
            </ul>
        </li>
        <li>Element de liste 2</li>
        <li>Element de liste 3</li>
        <li>Element de liste 4</li>
    </ul>
</div>

I was expecting both of the last two li's to remain unaffected, but only the very last one remained unchanged.

(As per the documentation: The :lt() selector targets all elements at an index less than the specified index within the matching set.)

Can someone explain why this behavior is occurring?

Answer №1

The starting point is always zero. If you want to target the initial five elements, you can achieve this by using:

$('li:lt(4)')

Courtesy of jQuery Documentation for :lt() selector:(Highlight added)

indexFromEnd: Starting from zero, counting in reverse order from the last item.

Remember that JavaScript arrays follow a zero-based numbering system, hence these selectors are aligned with that standard. This explains why $( ".myclass:lt(1)" ) picks the first element in the document with the class myclass, instead of returning nothing. On the other hand, :nth-child(n) uses a one-based index to comply with CSS conventions.

$(function() {
  $('li:lt(4)').css("background", "red");
});
<script src="https://code.jquery.com/jquery-1.10.2.js"></script>

<div id="listes">
  <ul id="ul1">
    <li>
      List Element 1
      <ul id="ul2">
        <li>Child 1</li>
        <li>Child 2</li>
      </ul>
    </li>
    <li>List Element 2</li>
    <li>List Element 3</li>
    <li>List Element 4</li>
  </ul>
</div>

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