When I display HTML code like this
<div class="btn btn-pagination">
<i class="fa fa-angle-right"></i>
</div>
and want to replace fa fa-angle-right with myClass when the page loads.
I attempted:
$(document).ready(function () {
$('.btn.btn-pagination').children($('.fa.fa-angle-right').removeClass());
$('.btn.btn-pagination').children().addClass('myClass');
})
This approach did not work. Can you help me understand what I'm doing wrong here?
For a more efficient solution, it is recommended to access the DOM only once.
jQuery(document).ready(function($) {
return $('.btn.btn-pagination .fa.fa-angle-right')
.removeClass()
.addClass('foobaz')
;
});.foobaz { background: red; width: 200px; height: 100px; margin: 0 auto; }<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="btn btn-pagination">
<div class="fa fa-angle-right"></div>
</div>While your current code may work, an alternative method using a more efficient selector and jQuery chaining can be seen below:
Give this a try:-
$(document).ready(function () {
$('.btn.btn-pagination').children('.fa.fa-angle-right').removeClass().addClass('myClass');
});
OR
$(document).ready(function () {
$('div.btn.btn-pagination > i.fa.fa-angle-right').removeClass().addClass('myClass');
});
Web Development
<div class="btn btn-pagination">
<i class="fa fa-angle-right"></i>
</div>
JavaScript
$(document).ready(function(){
$(".fa .fa-angle-right").addClass('myClass');
$(".fa .fa-angle-right").removeClass('.fa-angle-right');
});
For a demonstration, click here.
Below is the code snippet:
HTML:
<div class="btn btn-pagination">
<i class="fa fa-angle-right"></i>
</div>
JS:
$(document).ready(function() {
$('.btn.btn-pagination > i').attr('class', 'myClass');
})
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