Currently, I am still new to HTML coding and experimenting with displaying specific sections of an image. The current code I have is this:
<img id="theImg" style="width:100%;" src="https://'myimage.jpg'" />
I'm struggling to figure out how to display only the bottom left quarter of the image without having to create a separate cropped image. Is there a way to achieve this?
If you are aware of the dimensions of your image, you can place it within a container that is half the width and height of the image while utilizing position: absolute; with the following configurations:
.wrapper {
width: 250px;
height: 150px;
overflow: hidden;
position: relative;
}
.wrapper img {
position: absolute;
bottom: 0;
left: 0;
}<div class="wrapper">
<img src="http://placehold.it/500x300/fa0" />
</div>By utilizing a div element with a background image and making some simple CSS modifications, you can achieve the desired effect:
#theImg {
height: 200px;
width: 200px;
display: block;
background-image: url('https://myimage.jpg');
background-position: bottom left;
}
Check out the working example on JsFiddle: https://jsfiddle.net/kekwdy2L/3/
Implement the background-image property along with the background-position:
#custom-background {
background-image: url('https://i0.wp.com/lovecuteanimals.objects.cdn.dream.io/wp-content/uploads/2016/01/Cute-Netherland-Dwarf-Rabbit.jpg?w=1160');
background-position: -220px -80px;
display: inline-block;
width: 200px;
height: 200px;
}<div id="custom-background"></div><style>
div {
height: desired height;
width: desired width;
background-image:url("desired image");
</style>
<div class="custom-div"></div>
If you are familiar with the dimensions of the image in pixels, one method to use is a css clip.
Although officially deprecated in the css specification, the replacement clip-path currently does not have widespread browser support.
For another way to achieve cropping, consider placing the <img> tag within a <div> as demonstrated in this helpful answer on Stack Overflow.
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