Separate the divs in a template into individual templates, or alternatively, utilize ng-if to display different divs within a single template

As a newcomer to AngularJS, I am seeking advice on the most efficient way to code for the given scenario:

Scenario: I have a single HTML template containing multiple divs, and I need to display only one div at a time based on specific conditions.

Two approaches I am considering are: 1.) Breaking the divs into separate small templates and using them in templateURL, or 2.) Utilizing ng-if to show and hide the required divs within the same single HTML template.

It is worth noting that the individual divs are displayed in a modal window.

I would greatly appreciate guidance on which approach is faster and more efficient.

javascripthtmlcssangularjs

Answer №1

The best approach varies depending on the complexity of your blocks.

If your blocks are intricate and resource-heavy, such as rows in a large table with the ability to be hidden, it is faster to utilize ng-show/ng-hide. This method simply hides elements with display:none without altering the DOM structure.

For simpler blocks, ng-switch or ng-if can be used without performance issues.

If you only need to display one block at a time, consider using ng-include with a dynamic template name. I have personally not experienced any performance issues with this method.

<div ng-include="templateName"></div>

<script type="text/ng-template" id="templateOne.html">
   Content for template one
</script>
<script type="text/ng-template" id="templateOne.html">
   Content for template two
</script>

$scope.$watchCollection('[condition1, condition2, ...]', function(conditionsArr){
     if(conditionsArr[0] && !conditionsArr[1]){
          $scope.templateName = 'templateOne.html';
     }else{
          $scope.templateName = 'templateTwo.html';
     }
});

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