Select two out of the three links from a repeating HTML structure using JQuery

Having difficulty creating an efficient jQuery selector to choose 2 out of 3 existing a elements within a repeating HTML structure.

Below is the code snippet. The goal is to select Link 1, Link 2, excluding Link 3. Keep in mind that the entire HTML structure (div.container) may appear multiple times, and I need Link 1 and Link 2 from all instances of the container class.

NOTE 1: Markup cannot be altered.

NOTE 2: Preferring a solution entirely based on selectors (avoiding calls to .find(), etc., as this selector will be combined with another one outside the scope of this question).

<div class="container">
    <h1>
        <a href="http://www.google.ca">Link 1</a>
    </h1>
    <div>
        <div class="left">
            <p>
                <a href="http://www.google.ca">Link 2</a>
            </p>
        </div>
        <div class="right">
            <a href="http://www.google.ca">Link 3</a>
        </div>
    </div>
</div>

A simple selector for a single container structure would be:

$(".container a:lt(2)");

However, if there are multiple container structures, the previous method only selects Link 1 and Link 2 from the initial container.

The following approach works for one or more container structures, but it's not ideal. Setting up various CSS path selectors seems inefficient.

$(".container h1 a, .container .left a");

In simpler terms, I want to "select all a tags within the container class that are not located within the right class." Is there a way to achieve this? Or should I stick with the two-CSS-path selector mentioned earlier?

Test Fiddle.

Answer №1

Here is a different approach to consider:

$(".container").find("a:lt(2)")

Check out the DEMO here

In addition, you may also want to explore using a separate selector outside of the scope of this question and then combining it with the selector provided in this answer. For example, you could use $('.myOtherSelector, .selectorFromThisQuestion'). This way, you can keep the solution simple by just using a single selector. However, if this is not possible, you can still combine them using $('.container').find('a:lt(2)').add('.myOtherSelector'). But as mentioned earlier, the first option is much cleaner. Give it a try and see if it fits your needs!

If you prefer a one-liner workaround, you can experiment with this code snippet below. Just remember that this method only works for the current markup structure. Any changes to the markup may result in breaking the code.

$(".container :nth-child(1) a").css('background-color','red');

Experience the DEMO here

Answer №2

To exclude specific elements, you can utilize the :not selector in your jQuery code like so:

$(".container a:not('.right a')")

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