pressing the button again will yield a new outcome

Question

pressing the button again will yield a new outcome

I am looking to disable a button (material ui) when it is clicked for the second time by setting disabled={true}. Unfortunately, I have not been able to find any examples related to this specific scenario on StackOverflow.

<Button
  onClick={this.startDraw.bind(this)}
  disabled={}
  startIcon={<Brush />}
>

Initially, the button is clickable and triggers an action when clicked. However, my goal is to make sure that when the same button is clicked again for the second time, it becomes disabled and cannot be clicked anymore.

javascript html css reactjs typescript

Answer 1

Answer №1

When using a Class component:

    state = {
    count: 0
    };
this.setState({ count: count + 1 }); // Ensure to use this line on your button click event

For the button section:

   <Button
    onClick={this.startDraw.bind(this)}
    disabled={state.count == 2}
    startIcon={<Brush />}
  />

If opting for a functional component, follow this approach:


   const [count , setCount ] = useState(0);
   setCount(count + 1) // Remember to utilize this line on your button triggering

    <Button
    onClick={this.startDraw.bind(this)}
    disabled={count == 2}
    startIcon={<Brush />}
/>

Answer 2

When using a Class component:

    state = {
    count: 0
    };
this.setState({ count: count + 1 }); // Ensure to use this line on your button click event

For the button section:

   <Button
    onClick={this.startDraw.bind(this)}
    disabled={state.count == 2}
    startIcon={<Brush />}
  />

If opting for a functional component, follow this approach:


   const [count , setCount ] = useState(0);
   setCount(count + 1) // Remember to utilize this line on your button triggering

    <Button
    onClick={this.startDraw.bind(this)}
    disabled={count == 2}
    startIcon={<Brush />}
/>

pressing the button again will yield a new outcome

Answer №1

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