Positioning a Duplicated Element with Precision in jQuery

I am having trouble positioning a cloned div using jQuery. Even when I try to add CSS to the cloned element using the .css() method, it only affects the text and not the entire element.

Here is a link to the fiddle for reference: https://jsfiddle.net/emilychews/xuup6va1/3/

If you click on the blue div, it will create a clone of itself.

For easy access, here is the code snippet:

$('#testdiv').click(function() {
  $(this).clone()
    .insertAfter('#testdiv');
});
#wrapper {
  width: 100%;
  height: 100%;
}

#testdiv {
  display: flex;
  flex-direction: column;
  justify-content: center;
  align-items: center;
  margin-top: 20px;
  box-sizing: border-box;
  padding: 10px;
  background-color: blue;
  color: white;
  height: 350px;
  width: 300px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="wrapper">
  <div id="testdiv">
    <h1>I am a div</h1>
    <p>with a blue background</p>
  </div>
</div>

Answer №1

When I implement the following code snippet, everything works smoothly:

$('#exampleElement').click(function() {
  $( this ).clone()
    .insertAfter('#exampleElement')
    .css({
      position: 'absolute',
      top: 0
    });
});

It's important to note that if your element has an ID, cloning it may result in invalid markup.

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