Modify the color of CSS for all elements except those contained within a specific parent using jQuery

I have a color picker that triggers the following jQuery script:

//event.color.toHex() = hex color code
$('#iframe-screen').contents().find('body a').css('color', event.color.toHex());

This script will change the color of all links within #iframe-screen. However, I want to exclude links that are inside #menu without having to loop through each link.

Is there a way to apply the CSS above to all links that are not within #menu? For example:

$('#iframe-screen').contents().find('body [not-parent]#menu a').css('color', event.color.toHex());

The #menu consists of a typical unordered list menu:

<ul id="menu">
<li><a href="">dont change</a></li>
<li><a href="">dont change</a></li>
<li><a href="">dont change</a></li>
</ul>
<a href="">change</a>
<div><a href="">change</a></div>
javascriptjquerycssdom

Answer №1

To exclude certain elements, you can utilize the jQuery .not() function in the following way:

$('#iframe-screen').contents().find('body a').not('#menu a').css('color', event.color.toHex());

Answer №2

Give this a try, utilizing .filter().

$('a').filter(function(){
 return $(this).closest('#menu').length == 0;
}).css('color',event.color.toHex());

Check out the DEMO here

Answer №3

A sophisticated approach is to enclose your material within 

<div class="content"></div>
and place your menu navigation outside the wrapper. Then, update .find('body a') with .find(.content a).

This method will execute more efficiently compared to utilizing a jQuery solution.

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