jQuery swap- enhancing the appearance of numerical values

I am looking to customize specific characters within my <code> tag. While searching online, I came across the .replace() function but encountered issues when trying to style numbers. My goal is to change their appearance without altering the text itself.

Below is the code snippet I am working with:

HTML

<code> $years = floor($diff / (365*60*60*24)); </code>

JS

('code').each(function()
{
    var text = $(this).text(); 
    var setan = text.replace(/\d+/g,'<int>'+'\d'+'</int>');
    $(this).html(setan); 
});

The current output is

$years = floor($diff / (d*d*d*d));

I aim to achieve an outcome like

$years = floor($diff / (<b>d</b>*<b>d</b>*<b>d</b>*<b>d</b>));

Answer №1

It's a good idea to utilize a CSS class for styling the element as shown below:

$('code').html(function() {
  var text = $(this).text();
  return text.replace(/\d+/g, '<span class="d">' + 'd' + '</span>');
});
code span.d {
  font-weight: bold;
  color: green;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<code> $years = floor($diff / (365*60*60*24)); </code>

Answer №2

If I understand correctly, you are looking to display numbers instead of letters like d.

To achieve this, you can use capture groups for replacement. Here is a sample code snippet showing how it can be done:

$("code").each(function() {
    var text = $(this).text();
    $(this).html(text.replace(/(\d+)/g, '<num>$1</num>')); // feel free to use any tags
});
num { 
    color: blue;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<code>$years = floor($diff / (365*60*60*24));</code>

Answer №3

I am looking to modify this code snippet to calculate the number of years more accurately:

$years = floor($diff / (<b>d</b>*<b>d</b>*<b>d</b>*<b>d</b>));

For a better replacement, try using <b></b> instead of <int></int> in the replacement text, and make use of .html(function(index, html){})

$("code").html(function(_, html) {
    return html.replace(/\d+/g,"<b>d</b>");
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<code> $years = floor($diff / (365*60*60*24)); </code>

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