Jquery isn't functioning properly, but I suppose everything else is functioning correctly

Question

Jquery isn't functioning properly, but I suppose everything else is functioning correctly

I'm struggling with this code that's supposed to create a basic slide show:

   <script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
    <script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jqueryui/1.8.18/jquery-ui.min.js"></script>
    <script type="text/javascript">
        function Slider()
        {
            $(".slider#1").show("fade",500);
        }
    </script>

Then, there's this div:

   <div class="slider">
        <img id="1" src="images/pic1.jpg" border="0" alt="Image"/>
        <img id="2" src="images/pic1.jpg" border="0" alt="Image"/>
        <img id="3" src="images/pic1.jpg" border="0" alt="Image"/>
     </div>

In addition, I have an onload function in the body to trigger the jQuery function when the body loads:

<body onload="Slider()">

However, nothing seems to be happening. Can anyone spot the error?

javascript jquery html css

Answer 1

Answer №1

Why CSS IDs should not start with numbers

A reminder that starting a CSS ID with a number is invalid, explained here: http://css-tricks.com/ids-cannot-start-with-a-number/

Correct way to select child element

To properly select the child element of .slider, utilize .slider #i1, details available here: http://api.jquery.com/descendant-selector/

Using $(document).ready

Recommendation to use $(document).ready(function(){}); over <body onload="Slider()">, more info can be found here: Difference between onload() and $.ready?

Your provided code snippet

<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jqueryui/1.8.18/jquery-ui.min.js"></script>
<script>
    function Slider()
    {
        $(".slider #i1").show("fade",500);
    }
    $(document).ready(function(){
        Slider();
    });
</script>

<div class="slider">
     <img id="i1" src="images/pic1.jpg" border="0" alt="Image"/>
     <img id="i2" src="images/pic1.jpg" border="0" alt="Image"/>
     <img id="i3" src="images/pic1.jpg" border="0" alt="Image"/>
</div>

Answer 2

Why CSS IDs should not start with numbers

A reminder that starting a CSS ID with a number is invalid, explained here: http://css-tricks.com/ids-cannot-start-with-a-number/

Correct way to select child element

To properly select the child element of .slider, utilize .slider #i1, details available here: http://api.jquery.com/descendant-selector/

Using $(document).ready

Recommendation to use $(document).ready(function(){}); over <body onload="Slider()">, more info can be found here: Difference between onload() and $.ready?

Your provided code snippet

<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jqueryui/1.8.18/jquery-ui.min.js"></script>
<script>
    function Slider()
    {
        $(".slider #i1").show("fade",500);
    }
    $(document).ready(function(){
        Slider();
    });
</script>

<div class="slider">
     <img id="i1" src="images/pic1.jpg" border="0" alt="Image"/>
     <img id="i2" src="images/pic1.jpg" border="0" alt="Image"/>
     <img id="i3" src="images/pic1.jpg" border="0" alt="Image"/>
</div>

Answer 3

Answer №2

Give this a shot:

$(".slider #1").show("fade",500);

The key change here is the addition of a space between .slider and #1. This means that the script will now search for an element with the id '1' specifically within an element that has the class 'slider'. Previously, it was searching for an element with the id 'id' and the class slider at the same time.

Answer 4

Give this a shot:

$(".slider #1").show("fade",500);

The key change here is the addition of a space between .slider and #1. This means that the script will now search for an element with the id '1' specifically within an element that has the class 'slider'. Previously, it was searching for an element with the id 'id' and the class slider at the same time.

Answer 5

Answer №3

Solving the issue

Your selector contains an error. Remember to include a space between the class and id. As Copy Devil mentioned in their response, CSS ids cannot start with a number, therefore...

$(".slider #i1").show("fade",500);

Best Practices

Instead of using onload tag in your body, it is recommended to follow this approach.

$(document).ready(function(){
    $(".slider #i1").show("fade",500);
});

This is referred to as unobtrusive javascript. It promotes separation of HTML and javascript for cleaner code structure.

Answer 6

Solving the issue

Your selector contains an error. Remember to include a space between the class and id. As Copy Devil mentioned in their response, CSS ids cannot start with a number, therefore...

$(".slider #i1").show("fade",500);

Best Practices

Instead of using onload tag in your body, it is recommended to follow this approach.

$(document).ready(function(){
    $(".slider #i1").show("fade",500);
});

This is referred to as unobtrusive javascript. It promotes separation of HTML and javascript for cleaner code structure.

Answer 7

Answer №4

It seems like the issue lies with the spacing. As mentioned by previous answers,

".slider#1"
//refers to an element with both class slider and id 1

as opposed to

".slider #1"
//refers to an element with id 1 that is a descendant of an element with class slider

Some have recommended using $(document).ready, but using body onload will work as well without needing any changes. (However, the former method is preferred.)

Answer 8

It seems like the issue lies with the spacing. As mentioned by previous answers,

".slider#1"
//refers to an element with both class slider and id 1

as opposed to

".slider #1"
//refers to an element with id 1 that is a descendant of an element with class slider

Some have recommended using $(document).ready, but using body onload will work as well without needing any changes. (However, the former method is preferred.)

Jquery isn't functioning properly, but I suppose everything else is functioning correctly

Answer №1

Why CSS IDs should not start with numbers

Correct way to select child element

Using $(document).ready

Your provided code snippet

Answer №2

Answer №3

Answer №4

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