`JQuery fadeOut seems to have a limitation where it only applies to the

I have a group of divs, each containing an anchor tag that triggers a JavaScript function (which uses AJAX to delete a row from a table). Here's an example setup:

 <div id="container">
   <div><a id="btn" onclick="deleteRow()">Delete</a></div>
   <div><a id="btn" onclick="deleteRow()">Delete</a></div>
   <div><a id="btn" onclick="deleteRow()">Delete</a></div>
   ... and so on
 </div>

Then I have this jQuery code;

  $("#btn").click(function() {
    $(this).parent("div").fadeOut();
  });

This code should fade out each clicked element, but it's only working for the first one. When I click on the buttons of the other elements, nothing happens.

I'm not very familiar with jQuery, so I'm unsure why this is occurring.

Answer №1

Utilizing classes over IDs for unique identification

IDs versus Classes

[...] only one ID can be assigned to an element using the id attribute. It is recommended to use classes instead of multiple IDs, with additional identifiers managed through other methods like scripts interacting with the DOM.

Benefits of Using Classes

Classes provide flexibility for CSS and Javascript functionality by allowing targeted selection and access to specific elements using class selectors or DOM-related functions.

Source

Illustrative Example

Snippet from HTML:

<div id="container">
    <div><a class="btn" onclick="SomeFunction()">Delete</a></div>
    <div><a class="btn" onclick="SomeFunction()">Delete</a></div>
    <div><a class="btn" onclick="SomeFunction()">Delete</a></div>
</div>

Corresponding jQuery Usage:

$(".btn").click(function() // Use a dot followed by the class name to target classes.
{
    $(this).parent("div").fadeOut();
});

Demonstration in Action


In addition, I suggest exploring the benefits of .on() method.

Answer №2

It is important to remember that each element on a page can only have one ID. If you find jQuery getting confused, try utilizing class or attribute selectors as an alternative solution.

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