Issue with jQuery's addClass() function not functioning properly on Internet Explorer versions 8, 9, and possibly others as well

Here is some basic HTML code:

<div class="stuff-choice">
  <div class="item a">
    <label class="signup-checkbox">
      <input type="checkbox" value="a" name="stuff[a][]" id="stuff_choice_" class="things">
      <strong>A</strong>
    </label>
  </div>
</div>

In this code, I have set up functionality where clicking on a checkbox with the CSS class .things will update the parent <div> with the CSS class .selected.

The JavaScript code for this feature:

$('.things').click(function() {     
    item = $(this).closest("div");
    if ($(this).attr('checked') != null)
        $(item).addClass('selected');
    else
        $(item).removeClass('selected');
});

This code works perfectly in Safari (mac & win) and Firefox (mac & win), but encounters issues in Internet Explorer.

If anyone has insights on why it may not work in IE, please let me know.

Thank you,

Alex

jquerycssinternet-explorer

Answer №1

Internet Explorer has a reputation for throwing errors when variables are not declared with the "var" prefix.

To avoid this issue, make sure to use the following syntax:

var item = $(this).closest("div");

Answer №2

Give this a shot, the closest function already provides a jQuery object so there is no need to wrap it in $(). Additionally, you can utilize the is() method to check if an element is checked or not.

$('.things').click(function() {     
    $item = $(this).closest("div");
    if ($(this).is(':checked'))
        $item.addClass('selected');
    else
        $item.removeClass('selected');
});

Answer №3

It appears that the issue lies with the object on which you are using the .addClass method.

element = $(this).closest("div");

By defining element as a jQuery object in the above line, there is no need to use the $(element) syntax in your subsequent code. Simply utilize element instead.

$('.items').click(function() {     
    element = $(this).closest("div");
    if ($(this).attr('checked') != null)
        element.addClass('highlighted');
    else
        element.removeClass('highlighted');
});

Answer №4

Instead of utilizing addClass('hide'), I opted for .prop('disabled', 'disabled') and it proved to be effective in my scenario.

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