Is there a single function that can handle multiple sliders sharing identical options?

Currently, I am utilizing jQuery UI to generate 6 sliders with identical options for a survey.

I am curious if there exists a method to merge all these sliders into one function while maintaining the ability to operate them individually?

If such a solution does exist, would it look something like this:

$('#slider').each(function () {
    var $this = $(this).closest('#slider');

    $($this).slider(
    {
        value: 100,
        min: 0,
        max: 100,
        step: 25,
        slide: function (event, ui) {
            $('#amount').val('$' + ui.value);
        }
    });
    $('#amount').val($('#slider').slider("value"));

Despite my efforts to research similar queries, I have yet to find a resolution. Currently, only the first slider out of the set of 6 is visible.

Answer №1

Uncertain about the problem at hand. This jsFiddle demo showcases a simple setup where moving any slider displays its value in the input field.

Utilizing jQuery

$('.slider').slider({
    slide: function(event, ui) {
        $('input:eq('+ $(this).index() +')').val(ui.value);
    }
});​

Markup

<div class="slider"></div>
<div class="slider"></div>
<div class="slider"></div>
<div class="slider"></div>
<div class="slider"></div>
<div class="slider"></div>
<input /><br />
<input /><br />
<input /><br />
<input /><br />
<input /><br />
<input />​

Edit: code updated based on feedback.

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