Is it possible to use v-if in conjunction with a style tag to specify a different source file? Alternatively, is there a more efficient method I

Question

Is it possible to use v-if in conjunction with a style tag to specify a different source file? Alternatively, is there a more efficient method I

I attempted the example provided below, but unfortunately, it did not function as expected. The reason behind my endeavor is that adding numerous modifiers (--tuned) to achieve the desired outcome seemed impractical. Therefore, I decided to try and link the css file based on a specific condition. However, I encountered difficulties in making this approach work. Is there a reason why this method failed? Furthermore, does anyone have suggestions for a more efficient alternative to using multiple modifiers?

<style v-if="!isTuningActive" lang="scss" src="./normal-version.scss"></style>
<style
  v-else
  lang="scss"
  src="./tuned-version.scss"
></style>

javascript css typescript vue.js

Answer 1

Answer №1

Have you considered breaking it down into individual components? It allows for each component to have its own unique styling.

Check out this helpful link on component basics in Vue.js

Answer 2

Have you considered breaking it down into individual components? It allows for each component to have its own unique styling.

Check out this helpful link on component basics in Vue.js

Answer 3

Answer №2

If you merge your individual scss files into one main stylesheet (for example, main.scss), you can then import that main.scss file into your parent component (such as App.vue).

This approach allows you to easily toggle between css classes in the given example instead of attempting to conditionally import stylesheets.

For instance, let's assume your new 'main.scss' file includes the following scss:

.tuned-version {
   p { color: red }
}

.untuned-version {
   p { color: blue } 
}

Subsequently, all you need to do is dynamically apply the respective class based on your isTuningActive property.

<div :class="isTuningActive ? 'tuned-version' : 'untuned-version">
    <p>My content</p>
</div>

Here are some helpful resources:

Guidance on compiling scss in Vue:
Learn about dynamic class binding in Vue: https://vuejs.org/guide/essentials/class-and-style.html#binding-html-classes

Answer 4

If you merge your individual scss files into one main stylesheet (for example, main.scss), you can then import that main.scss file into your parent component (such as App.vue).

This approach allows you to easily toggle between css classes in the given example instead of attempting to conditionally import stylesheets.

For instance, let's assume your new 'main.scss' file includes the following scss:

.tuned-version {
   p { color: red }
}

.untuned-version {
   p { color: blue } 
}

Subsequently, all you need to do is dynamically apply the respective class based on your isTuningActive property.

<div :class="isTuningActive ? 'tuned-version' : 'untuned-version">
    <p>My content</p>
</div>

Here are some helpful resources:

Guidance on compiling scss in Vue:
Learn about dynamic class binding in Vue: https://vuejs.org/guide/essentials/class-and-style.html#binding-html-classes

Is it possible to use v-if in conjunction with a style tag to specify a different source file? Alternatively, is there a more efficient method I

Answer №1

Answer №2

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