Imagine you have elements that look like this:
<div class="a b" data-one="1" data-two="2"></div>
<div class="c" data-one="1" data-two="2"></div>
<div class="b" data-one="1" data-two="2"></div>
Is there a way to select all divs that do not have the class name b, along with attributes data-one="1" and data-two="2"? How would you achieve this? Thank you!
How do you feel about this?
document.querySelectorAll('div:not(.b)[data-1="1"][data-2="2"]')
With the power of jQuery:
$('div:not(.b)[data-one="1"][data-two="2"]')
Using vanilla JavaScript and querySelectorAll:
document.querySelectorAll('div:not(.b)[data-one="1"][data-two="2"]')
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