Is it considered secure to encase a function within jQuery's removeClass()?

I'm currently developing a unique slider that includes a dynamic video element. With each slide transition, a new video is added to the DOM while the previous one is removed. To achieve this effect, I am utilizing CSS transitions along with a specific class to animate the video's position. Here is what I aim for the function to do:

1) Apply a CSS class to the old video

2) Remove or detach the old video using either remove() or detach()

3) Apply a CSS class to the new video

The code snippet I have implemented so far is as follows:

function videoDetach() {

    // Restore loading spinner
    $('.spinnerMsg').removeClass("nospin");

    // Move video out of view and bring in the next one
    $('#bgIn video:first').removeClass( function (){
        $('#bgIn video:first').addClass("outview");
        setTimeout(function(){ 
            $('#bgIn video:first').detach();
            $('#bgIn video:last').addClass("inview");
        },250);
    });
}

While this code works correctly, I am unsure about its safety and correctness. What would be the best practice for achieving this task effectively?

In regards to choosing between detach() and remove(), since each video will be re-inserted as the slider repeats, detach() seems like the suitable option. However, I am uncertain about storing multiple videos in the DOM with the same id, and whether using remove(); would require users to download the entire video again.

Your feedback on this matter would be highly appreciated.


UPDATE

After making adjustments based on T.J's response due to some instability issues such as detaching all videos or permitting duplicates, the revised code now appears as follows:

function videoDetach() {

    // Restore loading spinner
    $('.spinnerMsg').removeClass("nospin");

    // Move current video out of view
    $('#bgIn video').addClass("outview");

    setTimeout(function(){ 
        $('#bgIn video.outview').detach(); // Detach the old video
        $('#bgIn video').addClass("inview"); // Bring the new video into view
    },250);
}

Answer №1

The call to the removeClass function in this code is unnecessary and can be removed without affecting the outcome:

function videoDetach() {

    // restore loading spinner
    $('.spinnerMsg').removeClass("nospin");

    // move video out of screen and bring the next one in
    $('#bgIn video:first').addClass("outview");
    setTimeout(function(){ 
        $('#bgIn video:first').detach();
        $('#bgIn video:last').addClass("inview");
    },250);
}

When providing a function to jQuery's setter operations like removeClass, it will be called for each element in the set. The function is expected to return the specific class to remove from that element.

This code currently works because the function inside removeClass only executes if there is an element matching #bgIn video:first. If multiple elements were selected, the function would run multiple times, or not at all with no matches. If the operation affected different elements than intended, the result could have been unpredictable.

What is the recommended approach for handling this task?

Executing the code directly, avoiding unintended side effects caused by incorrect usage.

I'm unsure which method to choose; since each video will be reinserted as the slider loops, detach() appears favorable. Is it acceptable to have multiple videos with the same id in the DOM?

If elements are detached, they do not exist in the DOM. It's permissible to have an element outside the DOM with the same id as one within. However, based on the provided code, you're detaching the video element (not identified by an id), not the #bgIn element.

Will using remove(); force users to download the entire video again?

No, the browser's cache does not distinguish between individual elements for redownloading content.

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