Having all elements at the same height

Question

Having all elements at the same height

I am looking to enhance my JavaScript code to only impact 4 items at a time. The goal is to target the first 4 instances of .prodbox, adjust their height accordingly, then move on to the next set of 4 and repeat the process. This sequential adjustment will ensure that each line of "Product Boxes" appears uniform and in alignment with itself.

The purpose of this enhancement is to ensure that product boxes with varying name lengths look visually aligned when displayed together. For example, in this image: https://i.stack.imgur.com/QvPJJ.png, you can see how adjusting the heights creates a more cohesive appearance even when dealing with products of different name lengths.

Below is the current version of my JavaScript code:

$(window).bind('load',function(){
    var largestHeight=0;
    $('.prodbox').each(function(){
        var prodbox=$(this);
        var prodboxHeight=prodbox.height();
        if(prodboxHeight>largestHeight){
            largestHeight=prodboxHeight}
        });
$('.prodbox').height(largestHeight)});

javascript jquery html css

Answer 1

Answer №1

DEMO

$(".prodbox").each(function(i){
    i++;
    $rowNumber = (Math.ceil(i/4) - 1)*4;
    $maxHeight = Math.max(
            $(".prodbox").eq($rowNumber).height(),
            $(".prodbox").eq($rowNumber+1).height(),
            $(".prodbox").eq($rowNumber+2).height(),
            $(".prodbox").eq($rowNumber+3).height()
        );
    $(this).height($maxHeight);
});

Answer 2

DEMO

$(".prodbox").each(function(i){
    i++;
    $rowNumber = (Math.ceil(i/4) - 1)*4;
    $maxHeight = Math.max(
            $(".prodbox").eq($rowNumber).height(),
            $(".prodbox").eq($rowNumber+1).height(),
            $(".prodbox").eq($rowNumber+2).height(),
            $(".prodbox").eq($rowNumber+3).height()
        );
    $(this).height($maxHeight);
});

Answer 3

Answer №2

In the scenario where your HTML structure consists of rows of .prodbox elements nested inside a container (given the class line), it may look something like this:

<div class="line">
     <div class="prodbox"></div>
     <div class="prodbox"></div>
     <div class="prodbox"></div>
     <div class="prodbox"></div>
</div>
<div class="line">
     <div class="prodbox"></div>
     <div class="prodbox"></div>
     <div class="prodbox"></div>
     <div class="prodbox"></div>
</div>

To iterate through the line elements and access all .prodbox elements within each line using JQuery's find method, you can use JavaScript code similar to the following (not tested):

$(window).bind('load',function(){
    var largestHeight=0;
    $('.line').each(function () {
        $(this).find('.prodbox').each(function() {
            var prodbox=$(this);
            var prodboxHeight=prodbox.height();
            if(prodboxHeight>largestHeight){
                largestHeight=prodboxHeight}
            });
        $('.prodbox').height(largestHeight)});
    });

Answer 4

In the scenario where your HTML structure consists of rows of .prodbox elements nested inside a container (given the class line), it may look something like this:

<div class="line">
     <div class="prodbox"></div>
     <div class="prodbox"></div>
     <div class="prodbox"></div>
     <div class="prodbox"></div>
</div>
<div class="line">
     <div class="prodbox"></div>
     <div class="prodbox"></div>
     <div class="prodbox"></div>
     <div class="prodbox"></div>
</div>

To iterate through the line elements and access all .prodbox elements within each line using JQuery's find method, you can use JavaScript code similar to the following (not tested):

$(window).bind('load',function(){
    var largestHeight=0;
    $('.line').each(function () {
        $(this).find('.prodbox').each(function() {
            var prodbox=$(this);
            var prodboxHeight=prodbox.height();
            if(prodboxHeight>largestHeight){
                largestHeight=prodboxHeight}
            });
        $('.prodbox').height(largestHeight)});
    });

Answer 5

Answer №3

To improve the layout, consider enclosing each row within a div tagged with a "row" class. This way, you can easily loop through each row and implement your preferred coding solution.

$(window).bind('load',function(){
    $('.row').each(function () {
        var tallestHeight=0;
        $(this).children('.prodbox').each(function(){
            var prodbox=$(this);
            var prodboxHeight=prodbox.height();
            if(prodboxHeight>tallestHeight) {
                tallestHeight=prodboxHeight
            }
        });
        $(this).children('.prodbox').height(tallestHeight);
    });
});

Answer 6

To improve the layout, consider enclosing each row within a div tagged with a "row" class. This way, you can easily loop through each row and implement your preferred coding solution.

$(window).bind('load',function(){
    $('.row').each(function () {
        var tallestHeight=0;
        $(this).children('.prodbox').each(function(){
            var prodbox=$(this);
            var prodboxHeight=prodbox.height();
            if(prodboxHeight>tallestHeight) {
                tallestHeight=prodboxHeight
            }
        });
        $(this).children('.prodbox').height(tallestHeight);
    });
});

Having all elements at the same height

Answer №1

Answer №2

Answer №3

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